esumate une difference hat you want 9976 confidenice hat your error is no more than 0.03. i Click the icon to view the discussion of sample size The sample should include men and women. (Type whole numbers.) - X Sample size discussion The sample size needed to estimate the difference between two population proportions to within a margin of error E with a confidence level of 1-a can be found by using the following expression: P,9, P292 E-Zal2 n Replace n, and n, by n in the preceding formula (assuming that both samples have the same size) and replace each of p,. 91. P2. and a, by 0.5 (because their values are not known). Solving for n results in this expression: 2E
esumate une difference hat you want 9976 confidenice hat your error is no more than 0.03. i Click the icon to view the discussion of sample size The sample should include men and women. (Type whole numbers.) - X Sample size discussion The sample size needed to estimate the difference between two population proportions to within a margin of error E with a confidence level of 1-a can be found by using the following expression: P,9, P292 E-Zal2 n Replace n, and n, by n in the preceding formula (assuming that both samples have the same size) and replace each of p,. 91. P2. and a, by 0.5 (because their values are not known). Solving for n results in this expression: 2E
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![**Sample Size Discussion**
The sample size needed to estimate the difference between two population proportions to within a margin of error \( E \) with a confidence level of \( 1 - \alpha \) can be found by using the following expression:
\[ E = z_{\alpha/2} \sqrt{\frac{p_1q_1}{n_1} + \frac{p_2q_2}{n_2}} \]
Replace \( n_1 \) and \( n_2 \) by \( n \) in the preceding formula (assuming that both samples have the same size) and replace each of \( p_1, q_1, p_2, \) and \( q_2 \) by 0.5 (because their values are not known). Solving for \( n \) results in this expression:
\[ n = \frac{z_{\alpha/2}^2}{2E^2} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7082471a-c94c-42b9-8c47-276f8b60d601%2F7c818726-bdee-4a7a-bc4b-778d1ff5e774%2Fdwsw3kg_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Sample Size Discussion**
The sample size needed to estimate the difference between two population proportions to within a margin of error \( E \) with a confidence level of \( 1 - \alpha \) can be found by using the following expression:
\[ E = z_{\alpha/2} \sqrt{\frac{p_1q_1}{n_1} + \frac{p_2q_2}{n_2}} \]
Replace \( n_1 \) and \( n_2 \) by \( n \) in the preceding formula (assuming that both samples have the same size) and replace each of \( p_1, q_1, p_2, \) and \( q_2 \) by 0.5 (because their values are not known). Solving for \( n \) results in this expression:
\[ n = \frac{z_{\alpha/2}^2}{2E^2} \]
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