ESTION 6 nufacturer needs to test to see the proportion of faulty products they produce. How large of a sample must the onfidence interval for this proportion with a width no greater than 14%
ESTION 6 nufacturer needs to test to see the proportion of faulty products they produce. How large of a sample must the onfidence interval for this proportion with a width no greater than 14%
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![### QUESTION 6
A manufacturer needs to test to see the proportion of faulty products they produce. How large of a sample must they use to get a 99% confidence interval for this proportion with a width no greater than 14%?
---
**Explanation:**
To determine the appropriate sample size for a confidence interval, consider the following steps:
1. **Identify the Desired Confidence Level:** Here, it is 99%.
2. **Determine the Maximum Acceptable Width of the Confidence Interval:** In this case, it is 14%.
3. **Estimate the Proportion of Faulty Products (p):**
- Without a preliminary estimate, use p = 0.5 for the worst-case scenario, as it maximizes the sample size requirement.
4. **Use the Equation for Sample Size (n):**
The formula for calculating the sample size for a proportion is:
\[
n = \left( \frac{Z^2 \cdot p \cdot (1 - p)}{E^2} \right)
\]
Where:
- \( n \) = required sample size
- \( Z \) = Z-value (from the Z-table corresponding to the desired confidence level)
- \( p \) = estimated proportion of faulty products
- \( E \) = maximum acceptable error (half the width of the confidence interval)
5. **Find the Z-value for 99% Confidence:**
- The Z-value for a 99% confidence level is approximately 2.576.
6. **Calculate the Required Sample Size:**
- Assuming p = 0.5 and E = 0.07 (since 14% width means ±7%):
\[
n = \left( \frac{2.576^2 \cdot 0.5 \cdot (1 - 0.5)}{0.07^2} \right)
\]
- Simplify the calculation to find n.
This step-by-step approach will guide how to determine the necessary sample size to achieve the desired confidence interval.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff5fb381f-811c-41ea-92d9-ccdf3c6fabee%2F402f03d7-a15d-408a-bab9-ab6bcf2deb33%2Fziplznq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### QUESTION 6
A manufacturer needs to test to see the proportion of faulty products they produce. How large of a sample must they use to get a 99% confidence interval for this proportion with a width no greater than 14%?
---
**Explanation:**
To determine the appropriate sample size for a confidence interval, consider the following steps:
1. **Identify the Desired Confidence Level:** Here, it is 99%.
2. **Determine the Maximum Acceptable Width of the Confidence Interval:** In this case, it is 14%.
3. **Estimate the Proportion of Faulty Products (p):**
- Without a preliminary estimate, use p = 0.5 for the worst-case scenario, as it maximizes the sample size requirement.
4. **Use the Equation for Sample Size (n):**
The formula for calculating the sample size for a proportion is:
\[
n = \left( \frac{Z^2 \cdot p \cdot (1 - p)}{E^2} \right)
\]
Where:
- \( n \) = required sample size
- \( Z \) = Z-value (from the Z-table corresponding to the desired confidence level)
- \( p \) = estimated proportion of faulty products
- \( E \) = maximum acceptable error (half the width of the confidence interval)
5. **Find the Z-value for 99% Confidence:**
- The Z-value for a 99% confidence level is approximately 2.576.
6. **Calculate the Required Sample Size:**
- Assuming p = 0.5 and E = 0.07 (since 14% width means ±7%):
\[
n = \left( \frac{2.576^2 \cdot 0.5 \cdot (1 - 0.5)}{0.07^2} \right)
\]
- Simplify the calculation to find n.
This step-by-step approach will guide how to determine the necessary sample size to achieve the desired confidence interval.
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