Estimate the population mean by finding a 99% confidence interval given a sample of size 35, with a mean of 63.2 and a standard deviation of 6.8. Preliminary: a. Is it safe to assume that n < 0.05 of all subjects in the population? O No O Yes b. Is n > 30? Yes O No Confidence Interval: What is the 99% confidence interval to estimate the population mean? Enter your answer as an open-interval (i.e., parentheses) accurate to one decimal place.

Q: uct a 90% confidence interval to estimate the population mean using the data below. = 80 6 = 15 n=…

A: The given information are: x¯=80, σ=15, n=40 and N=400. Where n is the sample size, x¯ is the sample…

Q: Estimate the population mean by finding a 99.9% confidence interval given a sample of size 70, with…

A: a. Yes, it is safe to assume that n ≤0.05 of all subjects in the population. b. Yes, the sample size…

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Q: Construct the confidence interval for the population mean u. c=0.95 x=15.6 and standard deviation =…

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Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: According to the given information, we have Confidence interval = (0.690, 0.718)

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Q: In a random sample of eleven people, the mean driving distance to work was 18.2 miles and the…

A: Confidence intervals are used to study the range where the population parameter is likely to occur.…

Q: Assume that a sample is used to estimate a population mean . Find the 95% confidence interval for a…

A: given data n = 41x¯ = 54.6σ = 7.395% ci for μ = ?

Q: Estimate the population mean by finding a 99% confidence interval given a sample of size 9, with a…

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Q: Construct the confidence interval for the population mean μ.   c=0.90​, x=16.3​, σ=5.0​, and n=95…

A: Construct the confidence interval for the population mean μ.   c=0.90​, x=16.3​, σ=5.0​, and n=95…

Q: A statistics practitioner took a random sample of 43 observations from a population whose standard…

A: We have given that,  sample mean (x̄) = 109, standard deviation (σ) = 30 and sample size (n) = 43

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Confidence interval=(0.729​,0.755​) Find margin of error=E

Q: Compute a confidence interval (95% interval, 2-tailed) for a mean. Data: sample mean = 38.5; sample…

A: Given, x¯=38.5s=8n=22α=0.05

Q: What percentage of hospitals provide at least some charity care? Based on a random sample of 10…

A: Solution: a. Let X be the percentage of hospitals provide at least some charity care. From the given…