Estimate the molar volume of nitrogen gas at 273 K and 10 bar using the van der Waals equation of state. Parameters a and b for nitrogen are 1.37 L²bar.mol-2 and 0.0387 L.mol-¹, respectively. The universal gas constant is 8.314x10-2 L.bar. K¹.mol-¹. The van der Waals equation of state is: P=RT/(V-b) - a/V²

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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Estimate the molar volume of nitrogen gas at 273 K and 10 bar using the van der Waals
equation of state. Parameters a and b for nitrogen are 1.37 L²bar.mol-2 and 0.0387
L.mol-¹, respectively. The universal gas constant is 8.314x102 L.bar.K.mol-¹. The van
der Waals equation of state is:
P=RT/(V - b) - a/V²
Transcribed Image Text:Estimate the molar volume of nitrogen gas at 273 K and 10 bar using the van der Waals equation of state. Parameters a and b for nitrogen are 1.37 L²bar.mol-2 and 0.0387 L.mol-¹, respectively. The universal gas constant is 8.314x102 L.bar.K.mol-¹. The van der Waals equation of state is: P=RT/(V - b) - a/V²
Expert Solution
Step 1: given data

g i v e n space equals space T space equals space 273 space K
P space equals space 10 space b a r space equals space 10 space a t m
a space equals space 1.37 space L squared b a r asterisk times m o l to the power of negative 2 end exponent
b space equals space 0.0387 space L. m o l to the power of negative 1 end exponent
R thin space equals space 8.314 asterisk times 10 to the power of negative 2 end exponent space L. b a r. K to the power of negative 1 end exponent m o l to the power of negative 1 end exponent
t o space f i n d space equals space m o l r space v o l u m e

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