Estimate the entropy change of vaporization of benzene at 323.15 K (50°C). The vapor pressure of benzene is given by the equation: ln Psat/kPa = 13,8858 - 2788,51/(t/oC + 220,79) (a) Use Eq. (6.69) with an estimated value of A Vlv. Eq. (6.69) : dPsat/dT = ΔHlv/T.ΔVlv (b) Use the Clausius/Clapeyron equation of Ex. 6.5
Estimate the entropy change of vaporization of benzene at 323.15 K (50°C). The vapor pressure of benzene is given by the equation: ln Psat/kPa = 13,8858 - 2788,51/(t/oC + 220,79) (a) Use Eq. (6.69) with an estimated value of A Vlv. Eq. (6.69) : dPsat/dT = ΔHlv/T.ΔVlv (b) Use the Clausius/Clapeyron equation of Ex. 6.5
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Estimate the entropy change of vaporization of benzene at 323.15 K (50°C). The vapor
pressure of benzene is given by the equation:
ln Psat/kPa = 13,8858 - 2788,51/(t/oC + 220,79)
(a) Use Eq. (6.69) with an estimated value of A Vlv.
Eq. (6.69) : dPsat/dT = ΔHlv/T.ΔVlv
(b) Use the Clausius/Clapeyron equation of Ex. 6.5
Transcribed Image Text:For the assumptions made,
psat yv
psat yl
AZV = Z' – Z' =
= 1 - 0 = 1
RT
RT
Then by Eq. (6.87),
d In Psat
ΔΗν-R.
d(1/T)
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