estimate the difference in the amount of daily leisure time in hours of adults who have children under the age of 18 years and adults who do not have children under the age of 18 years. A random sample of 39 adults with children under the age of 18 years result in a mean daily leisure time of 4.2 hours with a standard deviation of 2.18 hours. A random sample of 42 adults with no children under the age of 18 years result in a mean daily leisure time of 5.5 hours with a standard deviation of 2.46 hours. Test the claim that adults with children under 18 have less time than without children under 18 at 5% significance level.

Q: The number of ants in a group is normally distributed with a mean of 67.0 and a standard deviation…

A: Let X be the random variable for the number of ants in a group. Given that, X~N(μ=67.0, σ=83.64)…

Q: According to one study, the average hours of sleep on a weeknight for men was 6.9 hours with a…

A:

Q: Find the time it takes the fastest 24.2% of the college students to find a parking spot in the…

A: The length of time it takes college students to find a parking spot in the library parking lot…

Q: A report about how American college students manage their finances includes data from a survey of…

A: Population mean = ? = 907 Sample S.D = s =205 Sample size = n =500 Sample mean = x̅ = 825

Q: A​ half-century ago, the mean height of women in a particular country in their 20s was 63.8 inches.…

A: Given data,μ=63.8σ=2.51If n=28P(X≥65.08)=?

Q: According to a research paper, the carbon monoxide exposure of someone riding a motorbike for 5 km…

A: From the provided information, Mean (µ) = 18.4 ppm Population standard deviation (σ) = 5.3 ppm X~N…

Q: A marketing researcher wants to estimate the mean amount spent per year​ ($) on a web site by…

A: Given information- Population mean, μ = $53 Sample size, n = 100 Sample mean, x-bar = $60 Sample…

Q: A researcher measures the lengths of 3-year-old yellow perch in a fish hatchery and finds that they…

A: From the provided information, Mean (µ) = 17.2 Standard deviation (σ) = 3.4 X~N (17.2, 3.4)

Q: a 2003 study, the Accreditation Council for Graduate Medical Education found that medical residents’…

A: The formula of standardized z score for normal distribution is given by

Q: According to a recent survey, the population distribution of number of years of  education for…

A: What is the standard error of mean?

Q: A marketing researcher wants to estimate the mean amount spent per year​ ($) on a web site by…

A: The summary of statistics is,

Q: A fire department in a rural county reports that its response time to fires is approximately…

A: Consider that a random variable x, defines the response time to fires.

Q: A banker finds that the number of times people use automated-teller machines (ATMs) in a year are…

A: Solution-: Given:μ=40,σ=11.2 We want to find  the proportion of customers who use ATMs between 30…

Q: UCES LIGHT BULBS, BULB NORMAL DISTRIBUTION WITH A MEAN OF 800 HOURS AND A STANDARD DEVIATION OF 40…

A: Answer Calculation:1. Calculate the z-score using the formula:      where:   - is the value we want…

Q: The combined SAT scores for students at a local high school are normally distributed with a mean of…

A: X follows a Normal distribution with mean = 1497 and S.D = 293 Then z=(x-mean)/SD = (x-1497)/293…

Q: A marketing researcher wants to estimate the mean amount spent per year (5) on a web site by…

A: Given information Hypothesized mean µ = $49 Sample size (n) = 130 Mean x̅ = $55 Standard deviation…

Q: A marketing researcher wants to estimate the mean amount spent per year​ ($) on a web site by…

A: Let, X = Amount spent per year​ ($) on a web site by membership member shoppers. Given that;…

Q: Suppose the scores of students on an exam are normally distributed with a mean of 454 and a standard…

A:

Q: State the appropriate null and alternative hypotheses. Ο H μ 906 H: H 906 H: u 906 Ο H: μ 906 H:u…

A: The appropriate null and alternative hypotheses are given below: Here, µ is the true mean balance.…

Q: A research study examined the effects of meditation on quality of sleep. Fifty individuals were…

A:

Q: A candy store sells about 8 million pieces of candy per day with a standard deviation of 300,000…

A: Given : Let X : Number candy that they sell in a given day           μ = 8 million i.e   Mean (μ) =…

Q: ​Full-time college students report spending a mean of 29 hours per week on academic​ activities,…

A: From the provided information, Mean (µ) = 29 hours Standard deviation (σ) = 4 X~N (29, 4) Here X be…

Q: A​ half-century ago, the mean height of women in a particular country in their 20s was 64.7 inches.…

A: Given that: X is normal Distributed with mean µ = 64.7 and standard deviation σ = 2.88 By using…

Q: A recent survey found that 61% of all adults over the age of fifty wear glasses for driving. In a…

A: Given that Given distribution is binomial. n=Random sample of 80 adult n=80 p=61% of adults over the…

Q: A banker finds that the number of times people use automated-teller machines (ATMs) in a year are…

A: The mean is 40 and the standard deviation is 11.

Q: A marketing researcher wants to estimate the mean amount spent per year ($) on a web site by…

A: Given values, n=100x¯=60s=55

Q: A marketing researcher wants to estimate the mean amount spent per year ($) on a web site by…

A: The sample size is 130, sample mean is 58, and sample standard deviation is 53.

Q: A student researcher compares the heights of American students and non-American students from the…

A: Suppose μ1, μ2 are the true mean heights of American students and non-American students,…

Q: Suppose the scores of students on an exam are normally distributed with a mean of 558 and a standard…

A:

Q: A banker finds that the number of times people use automated-teller machines (ATMs) in a year are…

A:

Q: According to the U.S. Bureau of Labor Statistics, all workers in America who had a bachelor's degree…

A: Let x̄ be the sample mean  n be the sample size  Population mean μ  σ be the  population standard…

Q: A manufacturer is producing metal rods, whose lengths are normally distributed with a mean of 65.0…

A: #.Given : length of rod follow normal distribution with mean=65 cm and standard deviations=0.3 cm…

Q: Assume the average amount of caffeine consumed daily by adults is normally distributed with a mean…

A: The detailed solution is as follows below:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.