Estimate the dielectric losses in the solid specimen subjected to an alternating field of 40KV/cm, has an absolute permittivity of 4.445 x10-11 and the loss angle of that solid dielectric material is 0.28647at Oman power frequency. And also the same specimen while subjected to 3 KV/cm DC supply with the resistance value of 10 Mega Ohm, then determine the heat generated in the specimen.

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Estimate the dielectric losses in the solid specimen subjected to an alternating field of 40KV/cm, has an absolute permittivity of 4.445 x10-11 and the loss angle of that solid dielectric material is 0.28647at Oman power frequency. And also the same specimen while subjected to 3 KV/cm DC supply with the resistance value of 10 Mega Ohm, then determine the heat generated in the specimen.

 
 
Expert Solution
Step 1

Given that 

E = 40 KV/cm

εr=4.445×10-11 

tanδ=0.28647

f= 50 Hz

Although formula for di-electric loss is 

Di-electronic loss=E2×f×εr×tanδ1.8×1012  W/cm3plugging valuesDi-electronic loss=40×40×106×50×4.445×10-11×0.286471.8×1012  W/cm3Di-electronic loss=56593.74×10-17    W/cm3   Di-electronic loss=5.659374×10-13    W/cm3   

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