Estimate one real root of f (x) = 0.95x3 - 5.9a2 + 10.9x - 6 using three iterations of Newton Raphson Method with xo = 3.5. What is the relative error after the third iteration? O 1.4 % O 0.35 % O 0.14 % O 0.014 %

Q: Iteración 1 2 N Xi f(x)=e²x -x-6 Tabla II - Método de Newton-Raphson f(x₂) f'(x₂) Ea (%) & (%)

A: Given, f(x)=e2x-x-6 x0 = 0.5, Es = 0.05% and Xreal =0.9708

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