Estimate cell potential Ag(s)|AgBr(s)||KBr(aq)||Cd(NO3)2(aq)|Cd the25 °C. Data: [KBr(ag)) = 0.050 molkgt; [Cd(NO3)2(ag)] = 0.010 molkg!.Consider: y+(Cd²+) = y±{Cd(NO3)2} e v-(Br) = y± (KBr); lon dissociation100 %; b° = 1 molkg-1.E®Cd2+ (aq) + 2e¯ → Cd(s)-0.40V2AGB1(s) + 2e¯ –→ 2Ag(s) + 2B1¯ (aq)+0.07 VA. Calculate the global reaction.B. The cell's default potential.

Solution: We know, in electrochemistry at anode oxidation takes place file at cathode reduction take…

Estimate cell potential Ag(s)|AgBr(s)||KBr(aq)||Cd(NO3)2(aq)|Cd the 25 °C. Data: [KBr(ag)] = 0.050 molkg1; [Cd(NO3)2(ag)] = 0.010 molkg1. Consider: y+(Cd²*) = y±{Cd(NO3)2} e y-(Br) - yt (KBr); lon dissociation 100 %; b° = 1 molkg. %3D %3D Cd2+ (aq) + 2e¯ → Cd(s) -0.40V

Estimate cell potential Ag(s)|AgBr(s)||KBr(aq)||Cd(NO3)2(aq)|Cd the 25 °C. Data: [KBr(ag)] = 0.050 molkg1; [Cd(NO3)2(ag)] = 0.010 molkg1. Consider: y+(Cd²*) = y±{Cd(NO3)2} e y-(Br) - yt (KBr); lon dissociation 100 %; b° = 1 molkg. %3D %3D Cd2+ (aq) + 2e¯ → Cd(s) -0.40V

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Estimate cell potential Ag(s)|AgBr(s)||KBr(aq)||Cd(NO3)2(aq)|Cd the
25 °C. Data: [KBr(ag)) = 0.050 molkgt; [Cd(NO3)2(ag)] = 0.010 molkg!.
Consider: y+(Cd²+) = y±{Cd(NO3)2} e v-(Br) = y± (KBr); lon dissociation
100 %; b° = 1 molkg-1.
E®
Cd2+ (aq) + 2e¯ → Cd(s)
-0.40V
2AGB1(s) + 2e¯ –→ 2Ag(s) + 2B1¯ (aq)
+0.07 V
A. Calculate the global reaction.
B. The cell's default potential.

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