5. What are the units of K? 4.From your graph find the specific charge,K, of copper ions by calculatingthe slope.5.What are the units of K?colon/Kg6.Estimate the error, AK, in your value and write the result as K ± AK.7.Calculate the charge carried by each copper ion in the solution.Slaep)8.Use the result above to calculate the charge of the electron e. How doesit compare with the standard value?Pf A-t 100 % I. PURPOSE:Is cakutate Hr Specifir charge8coper Taas ubickis the amant of chage curlied bup mit mo6sScopperIous.II. DATA AND DATA ANALYSIS:Enter your data of the masses, m, and m2 in kg as related to the current, I,in Ampere and time, t, in minutes in Table (10.1) below:1.7.Table(10.1)Current(I) | Time (t) Amount of chargeDeposited massm2ighlabiai Mcu (m2-m,)(Kg).m1(It)(A)(min)(Kg)(Kg)(Coulomb)0,6A0.8201036. 36.86| 36-51- 36.567.01/001-36.82 36.92D.2 x10 x 60 = 0A5.490.3A20D,9X 5x60= 2+D8.D. 0636.920,3A0141094X6x 0= 24036.16 36 6-3698=05 02Use the data in Table (10.1) to plot the amount of charge (It) versus themass of the deposited copper Mcu.3.What type of relationship do you see between Mcu and It?Direct Liser108

The specific charge of any particle is the charge per kilogram of the particle. Therefore unit of K…

Answered: especific charge,K, c

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especific charge,K, c

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

5. What are the units of K?

I. PURPOSE:
Is cakutate Hr Specifir charge8coper Taas ubick
is the amant of chage curlied bup mit mo6sScopperIous.
II. DATA AND DATA ANALYSIS:
Enter your data of the masses, m, and m2 in kg as related to the current, I,
in Ampere and time, t, in minutes in Table (10.1) below:
1.
7.
Table(10.1)
Current(I) | Time (t) Amount of charge
Deposited mass
m2
ighlabiai Mcu (m2-m,)
(Kg).
m1
(It)
(A)
(min)
(Kg)
(Kg)
(Coulomb)
0,6A
0.8
20
10
36. 36.86| 36-51- 36.56
7.01/001-
36.82 36.92
D.2 x10 x 60 = 0
A5.49
0.3A
20
D,9X 5x60= 2+D
8.
D. 06
36.92
0,3A
014
10
94X6x 0= 240
36.16 36 6-3698=
05 02
Use the data in Table (10.1) to plot the amount of charge (It) versus the
mass of the deposited copper Mcu.
3.
What type of relationship do you see between Mcu and It?
Direct Liser
108

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