**Question 1 of 10, Step 1 of 1**A marketing research company desires to know the mean consumption of meat per week among males over age 26. A sample of 952 males over age 26 was drawn and the mean meat consumption was 3.9 pounds. Assume that the population standard deviation is known to be 1.5 pounds. Construct the 90% confidence interval for the mean consumption of meat among males over age 26. Round your answers to one decimal place.**Answer**How to enter your answer:- Lower endpoint: ______- Upper endpoint: ______**Buttons and Features:**- Tables- Keypad- Keyboard Shortcuts**Options:**- Tutor- Skip- Try Similar- Submit Answer© 2020 Hawkes Learning(Note: The image does not contain any graphs or diagrams requiring explanation.)

Name: **Question 1 of 10, Step 1 of 1**A marketing research company desires
Uploaded: 2024-03-05T11:52:21.000Z
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Description: **Question 1 of 10, Step 1 of 1**A marketing research company desires to know the mean consumption of meat per week among males over age 26. A sample of 952 males over age 26 was drawn and the mean meat consumption was 3.9 pounds. Assume that the po

According to the sum, a marketing company desires to know about the mean consumption of meat per week among males over age 26. A sample of 952 males is taken. n= 952 the mean is x=3.9 standard deviation is s=1.5 We need to construct a 90% confidence interval. So, 90% confidence interval=x±zsn =3.9±1.645×1.5952 =3.9±0.07997 lower endpoint: 3.9-0.07997=3.82003 upper endpoint: 3.9+0.07997=3.97997