esearcher wanted to determine if carpeted rooms contain more bacteria than uncarpeted rooms. The table shows the results for the number of bacteria per cubic foot for both es of rooms. Un Carpeted 7.5 15.9 11.6 11.9 10.9 4.4 9.5 14.7 11 14 termine whether carpeted rooms have more bacteria than uncarpeted rooms at the a = 0.05 level of significance. Normal probability plots indicate that the data are approximately normal and boxplots indicate tha diers. ate the null and alternative hypotheses. Let population 1 be carpeted rooms and population 2 be uncarpeted rooms. A. Ho: H1 =P2 B. Ho: H1 H2 "c. Họ: H1 = P2 H: H >H2 D. Ho: H1 =42 H: *H2 termine the P-value for this hypothesis test. ralue = (Round to three decimal places as needed.)

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  • What is the P Value=
  • What is the T= 
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A researcher wanted to determine if carpeted rooms contain more bacteria than uncarpeted rooms. The table shows the results for the number of bacteria per cubic foot for both types of rooms.

| Full data set  | Carpeted | Uncarpeted |
|----------------|----------|------------|
|                | 7.5      | 4.4        |
|                | 11.9     | 4.9        |
|                | 10.9     | 7.4        |
|                | 15.9     | 11.1       |
|                | 9.5      | 5.8        |
|                | 14.7     | 8.9        |
|                | 11.6     |            |
|                | 14       | 7          |
|                |          | 4.3        |

Determine whether carpeted rooms have more bacteria than uncarpeted rooms at the α = 0.05 level of significance. Normal probability plots indicate that the data are approximately normal and boxplots indicate that there are no outliers.

State the null and alternative hypotheses. Let population 1 be carpeted rooms and population 2 be uncarpeted rooms.

- A. \( H_0: \mu_1 = \mu_2 \)
  \( H_1: \mu_1 < \mu_2 \)

- B. \( H_0: \mu_1 < \mu_2 \)
  \( H_1: \mu_1 > \mu_2 \)

- C. \( H_0: \mu_1 = \mu_2 \)
  \( H_1: \mu_1 > \mu_2 \) (Check marked)

- D. \( H_0: \mu_1 = \mu_2 \)
  \( H_1: \mu_1 \neq \mu_2 \)

Determine the P-value for this hypothesis test.

P-value = [ ] (Round to three decimal places as needed.)
Transcribed Image Text:A researcher wanted to determine if carpeted rooms contain more bacteria than uncarpeted rooms. The table shows the results for the number of bacteria per cubic foot for both types of rooms. | Full data set | Carpeted | Uncarpeted | |----------------|----------|------------| | | 7.5 | 4.4 | | | 11.9 | 4.9 | | | 10.9 | 7.4 | | | 15.9 | 11.1 | | | 9.5 | 5.8 | | | 14.7 | 8.9 | | | 11.6 | | | | 14 | 7 | | | | 4.3 | Determine whether carpeted rooms have more bacteria than uncarpeted rooms at the α = 0.05 level of significance. Normal probability plots indicate that the data are approximately normal and boxplots indicate that there are no outliers. State the null and alternative hypotheses. Let population 1 be carpeted rooms and population 2 be uncarpeted rooms. - A. \( H_0: \mu_1 = \mu_2 \) \( H_1: \mu_1 < \mu_2 \) - B. \( H_0: \mu_1 < \mu_2 \) \( H_1: \mu_1 > \mu_2 \) - C. \( H_0: \mu_1 = \mu_2 \) \( H_1: \mu_1 > \mu_2 \) (Check marked) - D. \( H_0: \mu_1 = \mu_2 \) \( H_1: \mu_1 \neq \mu_2 \) Determine the P-value for this hypothesis test. P-value = [ ] (Round to three decimal places as needed.)
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