es. The delay be re shown. The 1

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### TCP Congestion Control Example

Consider the figure below, where a TCP sender sends 8 TCP segments at \( t = 1, 2, 3, 4, 5, 6, 7, 8 \). Suppose the initial value of the sequence number is 0 and every segment sent to the receiver contains 100 bytes. The delay between the sender and receiver is 5 time units, and so the first segment arrives at the receiver at \( t = 6 \). The ACKs sent by the receiver at \( t = 6, 7, 8, 10, 11, 12 \) are shown. The TCP segments (if any) sent by the sender at \( t = 11, 13, 15, 16, 17, 18 \) are **not** shown. The segment sent at \( t = 4 \) is lost, as is the ACK segment sent at \( t = 7 \).

**Diagram Explanation:**
- **TCP Sender Timeline (Left Side):**
  - Data segments are sent consecutively from \( t = 1 \) to \( t = 8 \).
  - The segment at \( t = 4 \) is marked with an 'X' indicating it is lost.
  - ACK segments are retransmitted starting from \( t = 11 \). 

- **TCP Receiver Timeline (Right Side):**
  - The receiver receives data segments and sends ACKs in response.
  - ACKs are successfully received back at \( t = 6, 7, 8, 10, 11, 12 \).
  - The ACK for \( t = 7 \) is lost, as marked by an 'X'.

**Question:**
What does the sender do at \( t = 17 \)? You can assume for this question that no timeouts have occurred.

In the context of this scenario, understanding TCP retransmission and acknowledgment processes is crucial for managing data flow and ensuring successful communication over a network.
Transcribed Image Text:### TCP Congestion Control Example Consider the figure below, where a TCP sender sends 8 TCP segments at \( t = 1, 2, 3, 4, 5, 6, 7, 8 \). Suppose the initial value of the sequence number is 0 and every segment sent to the receiver contains 100 bytes. The delay between the sender and receiver is 5 time units, and so the first segment arrives at the receiver at \( t = 6 \). The ACKs sent by the receiver at \( t = 6, 7, 8, 10, 11, 12 \) are shown. The TCP segments (if any) sent by the sender at \( t = 11, 13, 15, 16, 17, 18 \) are **not** shown. The segment sent at \( t = 4 \) is lost, as is the ACK segment sent at \( t = 7 \). **Diagram Explanation:** - **TCP Sender Timeline (Left Side):** - Data segments are sent consecutively from \( t = 1 \) to \( t = 8 \). - The segment at \( t = 4 \) is marked with an 'X' indicating it is lost. - ACK segments are retransmitted starting from \( t = 11 \). - **TCP Receiver Timeline (Right Side):** - The receiver receives data segments and sends ACKs in response. - ACKs are successfully received back at \( t = 6, 7, 8, 10, 11, 12 \). - The ACK for \( t = 7 \) is lost, as marked by an 'X'. **Question:** What does the sender do at \( t = 17 \)? You can assume for this question that no timeouts have occurred. In the context of this scenario, understanding TCP retransmission and acknowledgment processes is crucial for managing data flow and ensuring successful communication over a network.
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