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ertical jet. If there is no energy loss, (Z, - Z,) = h. What is V2 ? Demonstrate that V3 = 0 if Z, – Z, = h

ertical jet. If there is no energy loss, (Z, - Z,) = h. What is V2 ? Demonstrate that V3 = 0 if Z, – Z, = h

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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**Vertical Jet Analysis** *Concept Overview:* In a vertical jet system, if there is no energy loss, the relationship \((Z_3 - Z_2) = h\) holds true. This implies the fluid reaches height \(Z_3\) as predicted by its initial potential energy. *Diagram Explanation:* - The diagram shows a vertical jet system with water flowing from a container through a pipe. - Point 1: Located inside the container at height \( h \). - Point 2: At the base of the jet where the fluid exits into the air. - Point 3: At the peak height reached by the fluid jet where \(Z_3\) is located. - Water exits from the container, travels up the pipe, and shoots vertically into the air. *Equations and Problems:* 1. **Determine \(V_2\):** - What is the velocity of the fluid at Point 2? 2. **Prove \(V_3 = 0\) if \(Z_3 - Z_2 = h\):** - Demonstrate that the velocity at the highest point of the jet (Point 3) becomes zero when \((Z_3 - Z_2)\) equals the vertical height \(h\). This setup illustrates conservation principles and energy transfer in fluid mechanics.
Transcribed Image Text:**Vertical Jet Analysis** *Concept Overview:* In a vertical jet system, if there is no energy loss, the relationship \((Z_3 - Z_2) = h\) holds true. This implies the fluid reaches height \(Z_3\) as predicted by its initial potential energy. *Diagram Explanation:* - The diagram shows a vertical jet system with water flowing from a container through a pipe. - Point 1: Located inside the container at height \( h \). - Point 2: At the base of the jet where the fluid exits into the air. - Point 3: At the peak height reached by the fluid jet where \(Z_3\) is located. - Water exits from the container, travels up the pipe, and shoots vertically into the air. *Equations and Problems:* 1. **Determine \(V_2\):** - What is the velocity of the fluid at Point 2? 2. **Prove \(V_3 = 0\) if \(Z_3 - Z_2 = h\):** - Demonstrate that the velocity at the highest point of the jet (Point 3) becomes zero when \((Z_3 - Z_2)\) equals the vertical height \(h\). This setup illustrates conservation principles and energy transfer in fluid mechanics.
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