erstand how you got [2 1 1]t at the bottom of the third picture I just need to know how you got the matrix with the negative square root of 6i in part c?

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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I understand how you got [2 1 1]t at the bottom of the third picture I just need to know how you got the matrix with the negative square root of 6i in part c?
6:30-0
1
2
R3 → R₁ + R3
1
6:30-0
1
-2
X3
→ R₂
1
-1
R3
V₁
R₂ →(-1) R₂
1 0 -2
690-0
0 1 -1
X3
R3 -2R₂
-1
02-2
2
1 0 -2
690-0
0 1 -1
X3
thus, we get
x1 2x3 = 0
x₂x3 = 0
let 3 = t
x₁ = 2t
x₂ = t
||
||
2t
t
=
t
=
?
√x
1
1
DO
11:39
←
Step3
c)
for 2 = √6i
-1
1
C÷900
-√бi
-2
-√бі
-1
R₁ →→ 6
R₂
1
1
1
6
(+90-0
6i
-2
-√бi
1
R₂
√бi R₁
-1
2
R3 R3 + R₁
02
1
2
R₂ - R₁
√6i
6
02
5√6i
6
-
6
5√6i
6
(**)00
-2
6
5√6i
6
2
6
1
6
6
√6i
-2-
Bi
x1
X2
-√бi
6
EX÷00
i(²√6+i)
5
6
X3
√6i
6
)0-0
x2
=
=
√x
DO
8
Transcribed Image Text:6:30-0 1 2 R3 → R₁ + R3 1 6:30-0 1 -2 X3 → R₂ 1 -1 R3 V₁ R₂ →(-1) R₂ 1 0 -2 690-0 0 1 -1 X3 R3 -2R₂ -1 02-2 2 1 0 -2 690-0 0 1 -1 X3 thus, we get x1 2x3 = 0 x₂x3 = 0 let 3 = t x₁ = 2t x₂ = t || || 2t t = t = ? √x 1 1 DO 11:39 ← Step3 c) for 2 = √6i -1 1 C÷900 -√бi -2 -√бі -1 R₁ →→ 6 R₂ 1 1 1 6 (+90-0 6i -2 -√бi 1 R₂ √бi R₁ -1 2 R3 R3 + R₁ 02 1 2 R₂ - R₁ √6i 6 02 5√6i 6 - 6 5√6i 6 (**)00 -2 6 5√6i 6 2 6 1 6 6 √6i -2- Bi x1 X2 -√бi 6 EX÷00 i(²√6+i) 5 6 X3 √6i 6 )0-0 x2 = = √x DO 8
ANSWERED
Monday, Aug 22, 2022
MATH ADVANCED-MATH
#2 how do I compute the eigenvalues and
eigenvectors?
CEN
6:9
Expert Answer
Step1
a)
compute the eigenvalues and eigenvectors of each
of the following matrices.
let
0 -1 1
A = 1 0 -2
+6:9
-1 2
solution
0
evaluate the eigenvalue of
|0 - A
-1
1 |
A =
?
0 -1 1
1 0
-1 2
√x
-2
0
Do
←
evaluate the eigenvalue of
0-A -1
1
1
-2 = 0
-1
0 - X
2
-1
Step2
b)
-1
1
-1 2 -λ
⇒ −λ (X² + 4) +(−λ − 2)+(2 − λ)= 0
⇒ −λ (A² + 4) −2X = 0
⇒ A (A² + 6) = 0
implies,
A₁ = 0
X² +6=0
⇒ λ₂ = √√√бi, λ3 = -√√√6i
0
1
-1
1
-A-20
evluate the eigenvectors for the corresponding
eigenvalues
for ₁
= 0
-1
0
2
R₁ R₂
1 0
0
0 - X
-1
"17"
5)
-1 2 0
1
90-0
1
30-0
L?
√x 8
Transcribed Image Text:ANSWERED Monday, Aug 22, 2022 MATH ADVANCED-MATH #2 how do I compute the eigenvalues and eigenvectors? CEN 6:9 Expert Answer Step1 a) compute the eigenvalues and eigenvectors of each of the following matrices. let 0 -1 1 A = 1 0 -2 +6:9 -1 2 solution 0 evaluate the eigenvalue of |0 - A -1 1 | A = ? 0 -1 1 1 0 -1 2 √x -2 0 Do ← evaluate the eigenvalue of 0-A -1 1 1 -2 = 0 -1 0 - X 2 -1 Step2 b) -1 1 -1 2 -λ ⇒ −λ (X² + 4) +(−λ − 2)+(2 − λ)= 0 ⇒ −λ (A² + 4) −2X = 0 ⇒ A (A² + 6) = 0 implies, A₁ = 0 X² +6=0 ⇒ λ₂ = √√√бi, λ3 = -√√√6i 0 1 -1 1 -A-20 evluate the eigenvectors for the corresponding eigenvalues for ₁ = 0 -1 0 2 R₁ R₂ 1 0 0 0 - X -1 "17" 5) -1 2 0 1 90-0 1 30-0 L? √x 8
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