Errors in an experimental transmission channel are found when the transmissionis checked bya certifier that detects missing pulses. The number of errors found in an eight-bit byte is arandom variable with the following distribution. Determine P(X> 7)O a. None among the choicesO b.0.1O c. 1O d.oF(x)=0.70.9x < 11

The given distribution is, Fx=0 x<10.7 1≤x<40.9 4≤x<71…

Answered: Errors in an experimental transmission…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A coffee shop claims that it takes 115 seconds, on average, to serve their customers coffeethrough the drive-thru. Lucy, a statistics student, decides to test this claim. She randomlyselects 15 orders and records the wait time it took for the customer to receive their coffee.Here are the times (in seconds). 85 122 135 100 153153 116 99 65 130175 113 188 142 134(a) Why is it important that Lucy selects a random sample of orders? (b) Lucy wants to make a confidence interval to estimate the true mean wait time. Explainthoroughly why Lucy has or has not satisfied the “normal” condition for constructing aconfidence interval. (c) The 95% confidence interval for the true mean wait time is (109.1, 145.6) seconds. Does theinterval provide convincing evidence that the coffee shop is lying about their claim? Explain.
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Assume that hybridization experiments are conducted with peas having the property that for offspring, there is a 0.75 probability that a pea has green pods. Assume that the offspring peas are randomly selected in groups of 12. Complete parts (a) through (c) below. a. Find the mean and the standard deviation for the numbers of peas with green pods in the groups of 12. The value of the mean is u= 9 peas. (Type an integer or a decimal. Do not round.) The value of the standard deviation is σ = 1.5 peas. (Round to one decimal place as needed.) b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high. Values of peas or fewer are significantly low. (Round to one decimal place as needed.)
K A study was done on proctored and nonproctored tests. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal A. Ho H1 H2 H₁ H₁ H₂ ỌC. Hồ Hi-12 H₁: Hy > H₂ 0 в. Но 141=12 H₁ H₁ H₂ O D. Ho 11 #₂2 H₁ H1 H₂ The test statistic, t, is (Round to two decimal places as needed) The P-value is (Round to three decimal places as needed.) State the conclusion for the test. Proctored Nonproctored H 144 n 34 CIXS 77.58 11.08 12 31 81.91 21.24 A. Reject Ho There is sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. OB. Fail to reject Ho. There is sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. C. Fail to reject Ho. There is not sufficient evidence to support the…
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Assume that hybridization experiments are conducted with peas having the property that for offspring, there is a 0.25 probability that a pea has green pods. Assume that the offspring peas are randomly selected in groups of 40. Complete parts (a) through (c) below. a. Find the mean and the standard deviation for the numbers of peas with green pods in the groups of 40. The value of the mean is u = peas. (Type an integer or a decimal. Do not round.) The value of the standard deviation is o =| peas. (Round to one decimal place as needed.) b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high. Values of peas or fewer are significantly low. (Round to one decimal place as needed.) Values of peas or greater are significantly high. (Round to one decimal place as needed.) c. Is a result of 2 peas with green pods a result that is significantly low? Why or why not? The result significantly low, because 2 peas with green pods is peas.…
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Let X be a random variable with the following PMF: X = k k=-5 k=-2 k=0 k=2 k=5 P(X=k) 0.3 0.05 0.05 0.2 0.4 What is the probability that X is a negative number. Group of answer choices 0.6 0.4 0.35 1

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