Equipment A has a first cost of P50000, salvage value of P2000, life of equipment of 5years and maintenance cost of P6000. Equipment B has a first cost of P150,000,salvage value of P6000, life of equipment of 15 years and maintenance cost of P3000.If the maximum rate or return is 12% annually for both equipment, find the ROR ofadditional investment of equipment B.Select the correct response:4.516.6913.457.52

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Answered: Equipment A has a first cost of P50000,…

Essentials Of Investments

11th Edition

ISBN:9781260013924

Author:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Publisher:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Chapter1: Investments: Background And Issues

Section: Chapter Questions

Problem 1PS

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You are required to investigate the following project: The initial Investment at n=0 is $100,000. The project life is 10 years. Estimated annual operating cost : 34,000. The required minimum return on the investment :14%. The salvage value 8,000. What is the minimum annual revenues that should be generated to make the project worthwhile? 97842 52758 81921 45716 O O O O
From the given values below, which machine should be selected using (a) Present worth Method and (b) Future worth Method if interest rate is 10% per year? Machine A B Initial Cost (Php) Annual Operating Cost 146,000 15,000 80,000 10,000 3 220,000 10,000 75,000 25,000 Annual Revenue Salvage Value Useful Life (years) 6
A company wants to undertake an investment and has two projects under consideration. Project 1 will have a useful life of 7 years whereas project 2 would have a useful life of 6 years. Project 1 would also require an initial investment of GHc300,000 plus an additional repair cost of GHc20,000 on year 6. Project 2 would also require an initial investment of GHc240,000 plus an additional repair cost of GHc25,000 in years 4 and 5. Project 1 and 2 have an estimated salvage value of GHc5000 and GHC3000 respectively. Due to different project risk, project 1 and project 2 would be evaluated at an interest rate of 10% and 12% per year respectively. Project profits are estimated to be GHc100,000 and GHc100,000 per year respectively for both projects starting at the end of year 1 till the end of their respective project lifespans. Using the NPV approach, determine which project the company must invest in.
Compare the Annual Worth of the two systems and identify the better option at MARR = 10% per year: Solar: First cost $1,500,000; AOC $-700,000; Salvage value $100,000; Life of 8 years Geothermal: First cost $2,250,000; AOC $-600,000; Salvage value $50,000; Life of 8 years Select the Geothermal System with a calculated AW of $-1,017,368 Select the Geothermal System with a calculated AW of $-727,591 Select the Solar System with a calculated AW of $-1,238, Select the Solar System with a calculated AW of $-972,416
You have been asked to evaluate two alternatives, X and Y, that may increase plant capacity for manufacturing high-pressure hydraulic hoses. The parameters associated with each alternative have been estimated. Which one should be selected on the basis of a present worth comparison at an interest rate of 13% per year? Why is yours the correct choice? Alternative First Cost X $-45,000 Maintenance cost, per $-9000 Year Salvage Value $1,000 Life 5 years Y $-55,000 $-4000 $6,500 5 years The present worth of alternative X is $ 13888 and that of alternative Y is $ 44459.4 Alternative X is selected by the company.
Alternative X has a first cost of 36000 an annual operating cost of 6900, and a salvage value of 11025 after 13 year. Alternative Y has a first cost of 37000 an annual operating cost of 7000, and a salvage value of 16280 after 13 year. If MARR of 13% per year, approximately what is the PW of each alternative? Select one: O a. PW of X= -77518 and PW of Y= -78067 O b. PW of X= -75990 and PW of Y= -76529 O c. PW of X= -76750 and PW of Y= -77294 O d. PW of X= -78293 and PW of Y= -78848
You have been asked to evaluate two alternatives, X and Y, that may increase plant capacity for manufacturing high-pressure hydraulic hoses. The parameters associated with each alternative have been estimated. Which one should be selected on the basis of a present worth comparison at an interest rate of 10% per year? Why is yours the correct choice? Alternative First Cost Maintenance cost, per Year Salvage Value Life X $-25,000 $-8000 $1,000 5 years Y $-55,000 $-2000 $2,000 5 years and that of alternative Y is $1 The present worth of alternative X is $. Alternativ (Click to select) is selected by the company.
A project study for the construction of an engineering building are under consideration. Based on the study the cost of the building is P6,500,000 with a life of 30 years and a salvage value of P400,000. Yearly maintenance and repair is P18,000. If the yield of the investment is 6%, determine the equivalent uniform annual cost. Select the correct response: 485,581.36 O 458,581.36 485,158.36 458,158.36
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A project with a life of 10 has an initial fixed asset investment of $25,620, an initial NWC investment of $2,440, and an annual OCF of −$39,040. The fixed asset is fully depreciated over the life of the project and has no salvage value. If the required return is 10 percent, what is the project's equivalent annual cost, or EAC? Show equations using excel.
A project with the following costs are under consideration to determine its profitability. Using the IRR comparison, and an annual MARR of 10% compounded semiannually, determine if the project should be executed. First cost Semiannual operating cost Semiannual income Salvage value Life in years a. IRR = 18.7% semiannual O b. IRR = 15.3% semiannual Oc. IRR = 16.9% semiannual Od. IRR = 17% semiannual : $45,000 : $10,000 : $20,000 : $20,,000 : 4 years
Check whether the project is accepted or rejected and recommend the best project, MARR=6% and n=8 years, using Payback period, ROI, NPV, Aw, IRR methods. ID Project I Project II increase Annual Initial Annual cost revenues initial Annual Salvage value annual salvage value running in cost revenues maintenance revnues cost 1910095 280000 60000 2000 28000 400000 72000 2000 40000 12000

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