In this experiment, you will prepare standard solutions for a calibration curve for the formation of FeSCN2+ complex by reacting different volumes of 0.200 M Fe(NO3)3 and 0.002 M NaSCN. You will use 0.05 M HNO3 for all dilutions. Using the table, calculate the equilibrium concentrations of FeSCN2+. Equilibrium ConcentrationFe[SCN]²*Vol of Fe+Vol of SCN-0.05 Μ ΗΝΟ,(mL)(mL)(mL)10.000.0010.0010.001.009.0010.002.008.0010.003.007.0010.004.006.0010.005.005.00

The molarity of Fe(NO3)3 solution is 0.200 M. The molarity of NaSCN solution is 0.002 M.The reaction that takes place between Fe3+ and SCN- is expressed as, Fe3++SCN-↔FeSCN2+ The given concentration and volume of NaSCN is less than that of Fe(NO3)3. Therefore, NaSCN is the limiting reactant for the above reaction. The molar ratio between SCN- and Fe[SCN]2+ is 1 : 1. The equilibrium concentration of Fe[SCN]2+ is equal to the concentration of NaSCN in each solution. FeSCN2+=SCN-......(1)For each trial the total volume of the solution is 20 mL. The concentration of SCN- in the first trial is calculated as, SCN-=0.002 M×0.00 mL20.00 mL=0.0 M According to equation (1), the concentration of Fe[SCN]2+ is 0.0 M. The concentration of SCN- in the second trial is calculated as, SCN-=0.002 M×1.00 mL20.00 mL=0.0001 M According to equation (1), the equilibrium concentration of Fe[SCN]2+ is 0.0001 M.The concentration of SCN- in the third trial is calculated as, SCN-=0.002 M×2.00 mL20.00 mL=0.0002 M According to equation (1), the equilibrium concentration of Fe[SCN]2+ is 0.0002 M. The concentration of SCN- in the fourth trial is calculated as, SCN-=0.002 M×3.00 mL20.00 mL=0.0003 M According to equation (1), the equilibrium concentration of Fe[SCN]2+ is 0.0003 M.The concentration of SCN- in the fifth trial is calculated as, SCN-=0.002 M×4.00 mL20.00 mL=0.0004 M According to equation (1), the equilibrium concentration of Fe[SCN]2+ is 0.0004 M. The concentration of SCN- in the sixth trial is calculated as, SCN-=0.002 M×5.00 mL20.00 mL=0.0005 M According to equation (1), the equilibrium concentration of Fe[SCN]2+ is 0.0005 M.Answer: The equilibrium concentration of Fe[SCN]2+ in each solution is 0.0001 M, 0.0002 M, 0.0003 M, 0.0004 M and 0.0005 M.