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Equilateral AABC is inscribed in a circle. P is any point on BC. Prove PA = PB + PC. (Hint: Use Ptolemy's Theorem.)

Equilateral AABC is inscribed in a circle. P is any point on BC. Prove PA = PB + PC. (Hint: Use Ptolemy's Theorem.)

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Equilateral AABC is inscribed in a circle. P is any point on BC. Prove PA = PB + PC. (Hint: Use Ptolemy's Theorem.)
Transcribed Image Text:Equilateral AABC is inscribed in a circle. P is any point on BC. Prove PA = PB + PC. (Hint: Use Ptolemy's Theorem.)
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