Equation is x^2+y^2 = 13, point (2,-3). Find the equation of the tangent OR normal at that point.

Q: what point is the tangent line to y=1+2e* - 3x parallel to 3x - y = 5 ?

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Q: Differentiate (x-2)2+(y-3)2=9 at (7/2, ((6+3√3)/2)). Then use it to determine the equation of the…

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Q: Determine the equation of the line tangent to the graph given by y = at the point x +1 (4, }).

A: To find the equation of the line tangent to the graph y=xx+1 at the point 4,25

Q: 8. y = (3x² + 7)²

A: y=(3x2+7)2

Q: -(-3 y= 2³ +9r 4 3r

A: