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Eq 1 PV = 10 + Eq 2 (1+i) (1-0) 10(1-0)¹ (1+i)¹ (1+i)² (1+i)³ PV = + 10(1-0)² 10(1-0)², 10(1-0)³ + 10(1+i), 10(1-1)⁰, 10(1-0)¹ (1-0) (1+i)⁰ (1+i)¹ + + Eq1-Eq2: PV (1-i) 10(1+i) (1-0) (1-0) + + 10(1-0) (1+i)⁰⁰ + TπUA = ΠΑ 10 Ө 10(1-0) ⁰⁰ (1+i)⁰⁰ 10(1-0)-1 (1+i) ∞0-1

Eq 1 PV = 10 + Eq 2 (1+i) (1-0) 10(1-0)¹ (1+i)¹ (1+i)² (1+i)³ PV = + 10(1-0)² 10(1-0)², 10(1-0)³ + 10(1+i), 10(1-1)⁰, 10(1-0)¹ (1-0) (1+i)⁰ (1+i)¹ + + Eq1-Eq2: PV (1-i) 10(1+i) (1-0) (1-0) + + 10(1-0) (1+i)⁰⁰ + TπUA = ΠΑ 10 Ө 10(1-0) ⁰⁰ (1+i)⁰⁰ 10(1-0)-1 (1+i) ∞0-1

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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This should end with the two equations canceling to 10/theta but I dont understand how or if I made an error somewhere. The piA that I typed is just showing that it should end in 10/theta

Eq 1 PV = 10 + Eq 2 (1+i) (1-0) 10(1-0)¹ 10(1-0)², 10(1-0)³ (1+i)¹ (1+i)² (1+i)³ PV = + 10(1+i)_ 10(1-i)⁰ _ 10(1–0)¹ (1-0) (1+i)⁰ (1+i)¹ + + Eq1-Eq2: PV - (1−i) (1-0) + + 10(1+i) (1-0) + + 10(1-0) ∞ (1+i)⁰⁰ + ΠΑ + = 10 Ө 10(1-0) ⁰⁰ (1+i)⁰ 10(1-0)∞0-1 (1+i)⁰⁰-1
Transcribed Image Text:Eq 1 PV = 10 + Eq 2 (1+i) (1-0) 10(1-0)¹ 10(1-0)², 10(1-0)³ (1+i)¹ (1+i)² (1+i)³ PV = + 10(1+i)_ 10(1-i)⁰ _ 10(1–0)¹ (1-0) (1+i)⁰ (1+i)¹ + + Eq1-Eq2: PV - (1−i) (1-0) + + 10(1+i) (1-0) + + 10(1-0) ∞ (1+i)⁰⁰ + ΠΑ + = 10 Ө 10(1-0) ⁰⁰ (1+i)⁰ 10(1-0)∞0-1 (1+i)⁰⁰-1
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