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ep sn Buisn 9 10 Long Answer Type Questions 12. Two particles of mass 200 g each are placed at a separation of 10 cm. Assume that the only forces acting on them are due to their gravitational attraction. Find the acceleration of each when they are allowed to move.

ep sn Buisn 9 10 Long Answer Type Questions 12. Two particles of mass 200 g each are placed at a separation of 10 cm. Assume that the only forces acting on them are due to their gravitational attraction. Find the acceleration of each when they are allowed to move.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Please tell answer of 12-13-14
ach 11. A mass of 40 kg is attracted by a mass of 25 kg lying at a distance of 2 m from it with a force of 1.67 x 10 N. Find the value of G using this data of revolution of the T, where is directly proportion complete one revolu mean distance of the Long Answer Type Questions 12. Two particles of mass 200 g each are placed at a separation of 10 cm. Assume that the only forces acting on them are due to their gravitational attraction. Find the acceleration of each when they are allowed to move. or The inverse squa 13. Three balls A, B and C are kept in a straight line. The separation between A and C is 1 m, and B is placed at the mid-point between them. The masses of A, B and C are 100 g, 200 g and 300 g respectively. Find the net gravitational force on each of the three balls. relationship. Say, a p the sun (mass = M time taken to comp sun is T, and v is the moving. 14. A particle of mass m, is kept at x = 0 and another of mass m, at x = r. When a third particle is kept Then velocity, v = it experiences no net gravitational force 4 at x = or due to the two particles. Find "2 m, Or Knowledge Capsule 2 or Gravitational Force and Planetary Motion Or Centripetal Force The force required to move an object in a circular path is called centripetal force, and it acts towards the centra of the circle. Newton concluded that the motion of the moon around the earth is due to the centripetal force provided by the force of attraction of the e was no centripetal force, the moon would along a straight line with uniform motion If an object of mass m moves w Combining equatic The centripetal fore in circular motion is g ere ed F = Since say that of t of v along a circular path of radius Therefore, using Newton's secon
Transcribed Image Text:ach 11. A mass of 40 kg is attracted by a mass of 25 kg lying at a distance of 2 m from it with a force of 1.67 x 10 N. Find the value of G using this data of revolution of the T, where is directly proportion complete one revolu mean distance of the Long Answer Type Questions 12. Two particles of mass 200 g each are placed at a separation of 10 cm. Assume that the only forces acting on them are due to their gravitational attraction. Find the acceleration of each when they are allowed to move. or The inverse squa 13. Three balls A, B and C are kept in a straight line. The separation between A and C is 1 m, and B is placed at the mid-point between them. The masses of A, B and C are 100 g, 200 g and 300 g respectively. Find the net gravitational force on each of the three balls. relationship. Say, a p the sun (mass = M time taken to comp sun is T, and v is the moving. 14. A particle of mass m, is kept at x = 0 and another of mass m, at x = r. When a third particle is kept Then velocity, v = it experiences no net gravitational force 4 at x = or due to the two particles. Find "2 m, Or Knowledge Capsule 2 or Gravitational Force and Planetary Motion Or Centripetal Force The force required to move an object in a circular path is called centripetal force, and it acts towards the centra of the circle. Newton concluded that the motion of the moon around the earth is due to the centripetal force provided by the force of attraction of the e was no centripetal force, the moon would along a straight line with uniform motion If an object of mass m moves w Combining equatic The centripetal fore in circular motion is g ere ed F = Since say that of t of v along a circular path of radius Therefore, using Newton's secon
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