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Entered Answer Preview Result 0100100010001000000000100000000000000000000000000000000000000000 0100100010001000000000100000000000000000000000000000000000000000 incorrect 01001000100010000000001000 00000000000000000000000000 01001000100010000000001000 incorrect 00000000000000000000000000 incorrect 000000000000000000000000000000000000000000000 000000000000000000000000000000000000000000000 incorrect incorrect incorrect 010100 010100 incorrect 0000000000000000000000000000 11100001101010100101111011110100 At least one of the answers above is NOT correct. 2 of the questions remain unanswered. (4 points) In this problem we will work through a round of DES. For notational simplicity, assume it is the first round. Please enter all answers as strings of 0's and 1's. The input is the 64 bit block 0000000000001000000000101000000000010000000000001000000000000000 Suppose that the subkey for the current round is this 48 bit number: 000010000000000000000000000000000000000000000000 What does the 64 bit state look like after the IP transformation is applied to the input? 010010001000100000000010000000000000000000000000000 Now find Lo and Ro, the left and right halves of the state. Lo = Ro= = 01001000100010000000001000 00000000000000000000000000 What is the result of applying the expansion box to Ro? E(RO) 00000000000000000000000000000000000000 What is the result of XORing the subkey with E(RO)? k1 E(R0) We now apply the S-box transformation. S(k1 E(RO)) = Finally we apply the permutation box to complete the function f. ƒ(R0) = P(S(k1 ☞ E(R0))) = 010100 We can now compute the state of DES going into the next round. L₁ = R1 0000000000000000000000000 1110000110101010010111101 0000000000000000000000000000 incorrect 11100001101010100101111011110100 incorrect

Entered Answer Preview Result 0100100010001000000000100000000000000000000000000000000000000000 0100100010001000000000100000000000000000000000000000000000000000 incorrect 01001000100010000000001000 00000000000000000000000000 01001000100010000000001000 incorrect 00000000000000000000000000 incorrect 000000000000000000000000000000000000000000000 000000000000000000000000000000000000000000000 incorrect incorrect incorrect 010100 010100 incorrect 0000000000000000000000000000 11100001101010100101111011110100 At least one of the answers above is NOT correct. 2 of the questions remain unanswered. (4 points) In this problem we will work through a round of DES. For notational simplicity, assume it is the first round. Please enter all answers as strings of 0's and 1's. The input is the 64 bit block 0000000000001000000000101000000000010000000000001000000000000000 Suppose that the subkey for the current round is this 48 bit number: 000010000000000000000000000000000000000000000000 What does the 64 bit state look like after the IP transformation is applied to the input? 010010001000100000000010000000000000000000000000000 Now find Lo and Ro, the left and right halves of the state. Lo = Ro= = 01001000100010000000001000 00000000000000000000000000 What is the result of applying the expansion box to Ro? E(RO) 00000000000000000000000000000000000000 What is the result of XORing the subkey with E(RO)? k1 E(R0) We now apply the S-box transformation. S(k1 E(RO)) = Finally we apply the permutation box to complete the function f. ƒ(R0) = P(S(k1 ☞ E(R0))) = 010100 We can now compute the state of DES going into the next round. L₁ = R1 0000000000000000000000000 1110000110101010010111101 0000000000000000000000000000 incorrect 11100001101010100101111011110100 incorrect

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Entered Answer Preview Result 0100100010001000000000100000000000000000000000000000000000000000 0100100010001000000000100000000000000000000000000000000000000000 incorrect 01001000100010000000001000 00000000000000000000000000 01001000100010000000001000 incorrect 00000000000000000000000000 incorrect 000000000000000000000000000000000000000000000 000000000000000000000000000000000000000000000 incorrect incorrect incorrect 010100 010100 incorrect 0000000000000000000000000000 11100001101010100101111011110100 At least one of the answers above is NOT correct. 2 of the questions remain unanswered. (4 points) In this problem we will work through a round of DES. For notational simplicity, assume it is the first round. Please enter all answers as strings of 0's and 1's. The input is the 64 bit block 0000000000001000000000101000000000010000000000001000000000000000 Suppose that the subkey for the current round is this 48 bit number: 000010000000000000000000000000000000000000000000 What does the 64 bit state look like after the IP transformation is applied to the input? 010010001000100000000010000000000000000000000000000 Now find Lo and Ro, the left and right halves of the state. Lo = Ro= = 01001000100010000000001000 00000000000000000000000000 What is the result of applying the expansion box to Ro? E(RO) 00000000000000000000000000000000000000 What is the result of XORing the subkey with E(RO)? k1 E(R0) We now apply the S-box transformation. S(k1 E(RO)) = Finally we apply the permutation box to complete the function f. ƒ(R0) = P(S(k1 ☞ E(R0))) = 010100 We can now compute the state of DES going into the next round. L₁ = R1 0000000000000000000000000 1110000110101010010111101 0000000000000000000000000000 incorrect 11100001101010100101111011110100 incorrect
Transcribed Image Text:Entered Answer Preview Result 0100100010001000000000100000000000000000000000000000000000000000 0100100010001000000000100000000000000000000000000000000000000000 incorrect 01001000100010000000001000 00000000000000000000000000 01001000100010000000001000 incorrect 00000000000000000000000000 incorrect 000000000000000000000000000000000000000000000 000000000000000000000000000000000000000000000 incorrect incorrect incorrect 010100 010100 incorrect 0000000000000000000000000000 11100001101010100101111011110100 At least one of the answers above is NOT correct. 2 of the questions remain unanswered. (4 points) In this problem we will work through a round of DES. For notational simplicity, assume it is the first round. Please enter all answers as strings of 0's and 1's. The input is the 64 bit block 0000000000001000000000101000000000010000000000001000000000000000 Suppose that the subkey for the current round is this 48 bit number: 000010000000000000000000000000000000000000000000 What does the 64 bit state look like after the IP transformation is applied to the input? 010010001000100000000010000000000000000000000000000 Now find Lo and Ro, the left and right halves of the state. Lo = Ro= = 01001000100010000000001000 00000000000000000000000000 What is the result of applying the expansion box to Ro? E(RO) 00000000000000000000000000000000000000 What is the result of XORing the subkey with E(RO)? k1 E(R0) We now apply the S-box transformation. S(k1 E(RO)) = Finally we apply the permutation box to complete the function f. ƒ(R0) = P(S(k1 ☞ E(R0))) = 010100 We can now compute the state of DES going into the next round. L₁ = R1 0000000000000000000000000 1110000110101010010111101 0000000000000000000000000000 incorrect 11100001101010100101111011110100 incorrect
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