Enter the value stored in each element of the given array after the following code executes: int a2[5] int y {0}; 1; a2[2] a2[y] a2 [y + 2] a2 [0] 6; a2[2] yi %3D a2[y] + 8; a2[1] * a2[2]; %3D a2[4] = a2[0] a2[y]; %3D - element at index 0 = element at index 1 = %3D element at index 2 = element at index 3 = element at index 4 = %3D
Enter the value stored in each element of the given array after the following code executes: int a2[5] int y {0}; 1; a2[2] a2[y] a2 [y + 2] a2 [0] 6; a2[2] yi %3D a2[y] + 8; a2[1] * a2[2]; %3D a2[4] = a2[0] a2[y]; %3D - element at index 0 = element at index 1 = %3D element at index 2 = element at index 3 = element at index 4 = %3D
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
Finish the C++ code,
![### Array Value Calculation Exercise
#### Problem Statement
Enter the value stored in each element of the given array after the following code executes:
```c
int a2[5] = {0};
int y = 1;
a2[2] = 6;
a2[y] = a2[2] - y;
a2[y + 2] = a2[y] + 8;
a2[0] = a2[1] * a2[2];
a2[4] = a2[0] - a2[y];
```
#### Answer the following:
- element at index 0 = [ ]
- element at index 1 = [ ]
- element at index 2 = [ ]
- element at index 3 = [ ]
- element at index 4 = [ ]
#### Explanation of Code Execution
1. **Initialization:**
```c
int a2[5] = {0};
```
This initializes an array `a2` of size 5 and sets all elements to 0.
```c
int y = 1;
```
Variable `y` is initialized to 1.
2. **Setting specific values:**
```c
a2[2] = 6;
```
The element at index 2 of the array `a2` is set to 6. Now the array looks like:
```
a2 = {0, 0, 6, 0, 0}
```
3. **Updating element using variable `y`:**
```c
a2[y] = a2[2] - y;
```
Since `y` is 1, this line updates `a2[1]` to be `a2[2] - 1` which is `6 - 1 = 5`. Now the array looks like:
```
a2 = {0, 5, 6, 0, 0}
```
4. **Updating element at offset index:**
```c
a2[y + 2] = a2[y] + 8;
```
This line updates `a2[3]` (since `y + 2` is 3) to be `a2[1] + 8` which is `5 + 8 = 13`. Now](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fad3ee529-81b1-486a-8459-b4eea2f68af5%2F00a86422-e533-4aa5-b54b-c0856e799269%2Fm1zc3g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Array Value Calculation Exercise
#### Problem Statement
Enter the value stored in each element of the given array after the following code executes:
```c
int a2[5] = {0};
int y = 1;
a2[2] = 6;
a2[y] = a2[2] - y;
a2[y + 2] = a2[y] + 8;
a2[0] = a2[1] * a2[2];
a2[4] = a2[0] - a2[y];
```
#### Answer the following:
- element at index 0 = [ ]
- element at index 1 = [ ]
- element at index 2 = [ ]
- element at index 3 = [ ]
- element at index 4 = [ ]
#### Explanation of Code Execution
1. **Initialization:**
```c
int a2[5] = {0};
```
This initializes an array `a2` of size 5 and sets all elements to 0.
```c
int y = 1;
```
Variable `y` is initialized to 1.
2. **Setting specific values:**
```c
a2[2] = 6;
```
The element at index 2 of the array `a2` is set to 6. Now the array looks like:
```
a2 = {0, 0, 6, 0, 0}
```
3. **Updating element using variable `y`:**
```c
a2[y] = a2[2] - y;
```
Since `y` is 1, this line updates `a2[1]` to be `a2[2] - 1` which is `6 - 1 = 5`. Now the array looks like:
```
a2 = {0, 5, 6, 0, 0}
```
4. **Updating element at offset index:**
```c
a2[y + 2] = a2[y] + 8;
```
This line updates `a2[3]` (since `y + 2` is 3) to be `a2[1] + 8` which is `5 + 8 = 13`. Now
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