Ensure that the loop displays only 5 asterisks for (int i = 1; i <= 10; i++) { Console.Write(""); }
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A: Coded using Java language.
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A: Given:
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A: Required:
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A: Answer: I have given answer in the brief explanation.
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A: your question is about True false let's solve the question
Q: include
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- Recall the following segment of Java code for computing the set-difference of two given arrays (note that the lines have been numbered for the sake of reference): (1) int[] a, b; (2) (3) (4) (5) (6) (7) (8) (9) (10) count=0; (11) for (int i=0; i<=a.length-1; i++) { (12) (13) (14) (15) (16) (17) (18) (19) (20) (21) (22) (23) } (24) (25) int[] ans = new int[count]; (26) for (int i=0; i<-count-1; count++) (27) // Input the arrays a and b here int[] tempAns; int count,j; boolean found; tempAns = new int[a.length]; found = false; j-e; while (j<-b.length-1 && !found) { if (a[i]==b[j]) found = true; j+; } if (!found) { tempAns[count]=a[i]; count++; } ans[i] = tempAns[i]; Suppose we want to modify the above code to compute the set union of the arrays a and b, i.e., the set of all elements that are in either a or b. Which of the following changes would accomplish that?/* yahtC */ #include <stdio.h> #include <string.h> #include <stdlib.h> #include <time.h> void seed(int argc, char ** argv){ srand(time(NULL)); // Initialize random seed if (argc>1){ int i; if (1 == sscanf(argv[1],"%d",&i)){ srand(i); } } } void instructions(){ printf("\n\n\n\n" "\t**********************************************************************\n" "\t* Welcome to YahtC *\n" "\t**********************************************************************\n" "\tYahtC is a dice game (very) loosely modeled on Yahtzee\n" "\tBUT YahtC is not Yahtzee.\n\n" "\tRules:\n" "\t5 dice are rolled\n" "\tThe user selects which dice to roll again.\n" "\tThe user may choose to roll none or all 5 or any combination.\n" "\tAnd then the user selects which dice to roll, yet again.\n" "\tAfter this second reroll the turn is scored.\n\n" "\tScoring is as follows:\n" "\t\t*\t50 points \t5 of a kind scores 50 points.\n" "\t\t*\t45 points \tNo pairs (all unique) scores 45…What occurs when using the ref or out keyword with an array parameter?
- In c++, Declare a constant “ SIZE = 5 ” Declare an array of ints , of size SIZE . Initializethat array to have the values 10, 12, 15, 19, 6 .– Write a loop that calculates and prints out the minimum value of the array.– Write a loop that calculates and prints out the maximum value of the array.– Write a loop that calculates and prints out the average value of the array.#include <stdio.h> struct Single { int num; }; void printSingle(int f) { int binaryNum[33]; int i = 0; while(f>0) { binaryNum[i] = f % 2; f = f/2; i++; } for (int j=i-1; j>= 0; j--) { printf("%d",binaryNum[j]); } } int main() { struct Single single; single.num = 33; printf("Number: %d\n",single.num); printSingle(single.num); return 0; }PrimeAA.java Write a program that will tell a user if their number is prime or not. Your code will need to run in a loop (possibly many loops) so that the user can continue to check numbers. A prime is a number that is only divisible by itself and the number 1. This means your code should loop through each value between 1 and the number entered to see if it’s a divisor. If you only check for a small handful of numbers (such as 2, 3, and 5), you will lose most of the credit for this project. Include a try/catch to catch input mismatches and include a custom exception to catch negative values. If the user enters 0, the program should end. Not only will you tell the user if their number is prime or not, you must also print the divisors to the screen (if they exist) on the same line as shown below AND give a count of how many divisors there are. See examples below. Your program should run the test case exactly as it appears below, and should work on any other case in general. Output…
- Computer Science Part C: Interactive Driver Program Write an interactive driver program that creates a Course object (you can decide the name and roster/waitlist sizes). Then, use a loop to interactively allow the user to add students, drop students, or view the course. Display the result (success/failure) of each add/drop.What is the output of this code? def func(a,b): if(b==1): return a else: return a* func(a,b-1) A It adds a and b (B) None of these choices © It multiplies a and b (D) It raises a to the power of b-0 FAMAS oro ag -0 1 void printVerticalGraph(int nUnits) { 2 4 9 10 11 12 13 14 15 16 17 456 BARHEIDEN 18 19 20 21 22 23 24 25 26 27 int nRev; printf("%d\n", nUnits); while (nUnits>0){ nRev = getReverse (nUnits); // 1) Adjust nUnits ?? [Q1] ?? while (nRev>0){ nUnits *= 10; // 2) Condition to print * if(?? [Q2]??) { printf("*"); } // 3) Update for nUnits for * case ?? [Q3] ?? }else{ printf(" "); // 4) Update for nUnits for ?? [Q4]?? } // 5) Update to nRev ?? [Q5]?? printf("\n"); case
- #include <stdio.h>#include <stdlib.h> int MAX_SIZE = 10;int n = 0; //A counter variable which will keep track of number of elements in arr. void append(int *arr, int element){ if(n == MAX_SIZE) { MAX_SIZE = MAX_SIZE * 2; int *ptr = (int*)malloc(MAX_SIZE * sizeof(int)); //Copy elements of existing array to a new array for(int i=0;i<n;i++) { ptr[i] = arr[i]; } arr = ptr; n++; } arr[n] = element;} int get(int *arr, int index){ return arr[index];}int main(){ int *arr = (int*)malloc(MAX_SIZE * sizeof(int)); n = 10; for(int i=0;i<n;i++) arr[i] = i+1; printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n); printf("\nArray: "); for(int i=0;i<n;i++) printf("%d ", arr[i]); printf("\n\nAdding an element"); append(arr, 11); printf("\nArray size: %d", MAX_SIZE); printf("\nNumber of elements: %d", n);…C++ Vector iteration: Sum of excess. Vector testGrades contains NUM_VALS test scores. Write a for loop that sets sumExtra to the total extra credit received. Full credit is 100, so anything over 100 is extra credit. Ex: If testGrades = {101, 83, 107, 90}, then sumExtra = 8, because 1 + 0 + 7 + 0 is 8.#include <stdio.h>#include <limits.h> int findMissingUtil(int arr[], int low, int high, int diff){ if (high <= low)return INT_MAX; int mid = low + (high - low)/2; if (arr[mid+1] - arr[mid] != diff)return (arr[mid] + diff); if (mid > 0 && arr[mid] - arr[mid-1] != diff)return (arr[mid-1] + diff); if (arr[mid] == arr[0] + mid*diff)return findMissingUtil(arr, mid+1, high, diff); return findMissingUtil(arr, low, mid-1, diff);} int findMissing(int arr[], int n){int diff = (arr[n-1] - arr[0])/n; return findMissingUtil(arr, 0, n-1,diff);} int main(){int arr[] = {120001, 120013, 120025, 120037, 120049, 120061,120085,120097,120109,120121};int n = sizeof(arr)/sizeof(arr[0]);printf("The missing element is %d", findMissing(arr, n));return 0;} ______________________________________________________________________________ Convert the code above into Pseudocode