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ength=7m height=250mm UDL on the beam=38.5KN/M d=812mm Mass of the beam=65.9kg/m a. Consider design loads( udl+self weight) b. Calculate and draw the Bending Moment Diagram (BDM). What is the value of the maximum bending moment? c. Calculate and draw the Shear Force Diagram (SFD). What is the value of the maximum shear force? d. Using the table, calculate the maximum deflection of the beam.

ength=7m height=250mm UDL on the beam=38.5KN/M d=812mm Mass of the beam=65.9kg/m a. Consider design loads( udl+self weight) b. Calculate and draw the Bending Moment Diagram (BDM). What is the value of the maximum bending moment? c. Calculate and draw the Shear Force Diagram (SFD). What is the value of the maximum shear force? d. Using the table, calculate the maximum deflection of the beam.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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length=7m height=250mm UDL on the beam=38.5KN/M d=812mm Mass of the beam=65.9kg/m

a. Consider design loads( udl+self weight)

b. Calculate and draw the Bending Moment Diagram (BDM).
What is the value of the maximum bending moment?

c. Calculate and draw the Shear Force Diagram (SFD).
What is the value of the maximum shear force?

d. Using the table, calculate the maximum
deflection of the beam.

Beam deflection formulae (extracted from http://www.roymech.co.uk/Useful_Tables/Timber/Timber_Strength_ Calcs.html) Loading Deflection Loading Deflection max max W total total 5WL3 WL L 384EI L 384EI W total P | b WL3 PL3 a L/2 L/2 384EI 192EI b>a PL3 2Pa’b L/2 48EI a b 3EIB b> a P| PL3 total a2 Wa'b 48ΕΙ 24EI аpprox. total total Wb. Wab3 Wa 13 a 8EI 6EI L 8EI Wb°, Wab? 3EΙ 3ΕΙ Pa a a L 3EI a, = (L³+ 2L?a + 4La? - 8a³ ) 4b +1 За 3b + 1 2a d2 B = (3L-2a)? P. II P.
Transcribed Image Text:Beam deflection formulae (extracted from http://www.roymech.co.uk/Useful_Tables/Timber/Timber_Strength_ Calcs.html) Loading Deflection Loading Deflection max max W total total 5WL3 WL L 384EI L 384EI W total P | b WL3 PL3 a L/2 L/2 384EI 192EI b>a PL3 2Pa’b L/2 48EI a b 3EIB b> a P| PL3 total a2 Wa'b 48ΕΙ 24EI аpprox. total total Wb. Wab3 Wa 13 a 8EI 6EI L 8EI Wb°, Wab? 3EΙ 3ΕΙ Pa a a L 3EI a, = (L³+ 2L?a + 4La? - 8a³ ) 4b +1 За 3b + 1 2a d2 B = (3L-2a)? P. II P.
L-d
Transcribed Image Text:L-d
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