ENGR 1310: Introduction to Engineering Fall 2020 Problem 4: Electric Circuits Find the equivalent resistance for the circuit shown below. 120 15 0 24 N 120N 60 n 20n 25 N b

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**ENGR 1310: Introduction to Engineering**  
*Fall 2020*

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**Problem 4: Electric Circuits**

Find the equivalent resistance for the circuit shown below.

**Diagram Description**:  
The circuit diagram consists of resistors connected in different configurations between points a and b. 

1. **From point a to b**:
   - A 15 Ω resistor is connected directly in parallel with another path.
   - In the parallel path, a 24 Ω resistor is connected in series with a 12 Ω resistor.
   - Both connections then reunite before reaching another branch.

2. **Another path from point a to b**:
   - In series with the first branch, a 120 Ω resistor is connected.
   - This is followed by a junction connecting a 60 Ω resistor in parallel with a 20 Ω resistor.
   
3. **Starting from a different path from point a to b**:
   - A separate 25 Ω resistor is in series with a 7 Ω resistor.

**Solution:**

*Note: To find the equivalent resistance, apply series and parallel resistance formulas to simplify each section step-by-step.*

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This text is prepared for educational purposes to illustrate the analysis and reduction of complex circuits using equivalent resistance techniques.
Transcribed Image Text:**ENGR 1310: Introduction to Engineering** *Fall 2020* --- **Problem 4: Electric Circuits** Find the equivalent resistance for the circuit shown below. **Diagram Description**: The circuit diagram consists of resistors connected in different configurations between points a and b. 1. **From point a to b**: - A 15 Ω resistor is connected directly in parallel with another path. - In the parallel path, a 24 Ω resistor is connected in series with a 12 Ω resistor. - Both connections then reunite before reaching another branch. 2. **Another path from point a to b**: - In series with the first branch, a 120 Ω resistor is connected. - This is followed by a junction connecting a 60 Ω resistor in parallel with a 20 Ω resistor. 3. **Starting from a different path from point a to b**: - A separate 25 Ω resistor is in series with a 7 Ω resistor. **Solution:** *Note: To find the equivalent resistance, apply series and parallel resistance formulas to simplify each section step-by-step.* --- This text is prepared for educational purposes to illustrate the analysis and reduction of complex circuits using equivalent resistance techniques.
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