Engineers want to design seats in commercial aircraft so that they are wide enough to fit 90% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 13.9 in. and a standard deviation of 0.8 in. Find Pao. That is, find the hip breadth for men that separates the smallest 90% from the largest 10%.
Engineers want to design seats in commercial aircraft so that they are wide enough to fit 90% of all males. (Accommodating 100% of males would require very wide seats that would be much too expensive.) Men have hip breadths that are normally distributed with a mean of 13.9 in. and a standard deviation of 0.8 in. Find Pao. That is, find the hip breadth for men that separates the smallest 90% from the largest 10%.
MATLAB: An Introduction with Applications
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Author:Amos Gilat
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![### Designing Aircraft Seats for Male Passenger Hip Breadth
**Objective:** Engineers seek to design seats in commercial aircraft that are sufficiently wide to fit 90% of all males. (Accommodating 100% of males would necessitate excessively wide seats and be prohibitively expensive.) The focus is on men whose hip breadths are normally distributed with a mean of 13.9 inches and a standard deviation of 0.8 inches. The task is to find P₉₀, the hip breadth that separates the smallest 90% from the largest 10%.
#### Introduction
**Normal Distribution Parameters:**
- Mean (μ): 13.9 inches
- Standard Deviation (σ): 0.8 inches
**Goal:** Find the hip breadth (P₉₀) that separates the smallest 90% from the largest 10% of the distribution.
#### Step-by-Step Process
1. **Determine the Z-score:**
Use technology to find the Z-score corresponding to the given area (90%). This is achieved through the Z-score table or statistical software/calculators.
2. **Concept of the 90th Percentile:**
- The 90th percentile, P₉₀, implies that 90% of the data falls below this value.
- Mathematically, it means the area under the normal curve to the left of x is equal to 0.9000.
**Graphical Representation:**
- A bell curve (normal distribution) shows a shaded area of 0.90 on the left side.
- There is a vertical line marking the mean (13.9 inches) and another at the value x, which signifies the 90th percentile.
3. **Calculation:**
- Use the Z-score formula:
\[ x = \mu + (z \cdot \sigma) \]
- Find z that corresponds to the shaded area of 0.9000.
- For Z = 1.28 (rounded to two decimal places).
**Conclusion:**
By substituting the known values into the formula:
\[ x = 13.9 + (1.28 \cdot 0.8) \]
\[ x = 13.9 + 1.024 \]
\[ x = 14.924 \]
Thus, the hip breadth separating the smallest 90% from the largest 10% of men is approximately 14.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7d7d641b-33fb-4b6a-a4ba-acdd814096ba%2F6790e8ea-9e82-4919-bd82-f94d8a233bae%2Fnmq5v5m_processed.png&w=3840&q=75)
Transcribed Image Text:### Designing Aircraft Seats for Male Passenger Hip Breadth
**Objective:** Engineers seek to design seats in commercial aircraft that are sufficiently wide to fit 90% of all males. (Accommodating 100% of males would necessitate excessively wide seats and be prohibitively expensive.) The focus is on men whose hip breadths are normally distributed with a mean of 13.9 inches and a standard deviation of 0.8 inches. The task is to find P₉₀, the hip breadth that separates the smallest 90% from the largest 10%.
#### Introduction
**Normal Distribution Parameters:**
- Mean (μ): 13.9 inches
- Standard Deviation (σ): 0.8 inches
**Goal:** Find the hip breadth (P₉₀) that separates the smallest 90% from the largest 10% of the distribution.
#### Step-by-Step Process
1. **Determine the Z-score:**
Use technology to find the Z-score corresponding to the given area (90%). This is achieved through the Z-score table or statistical software/calculators.
2. **Concept of the 90th Percentile:**
- The 90th percentile, P₉₀, implies that 90% of the data falls below this value.
- Mathematically, it means the area under the normal curve to the left of x is equal to 0.9000.
**Graphical Representation:**
- A bell curve (normal distribution) shows a shaded area of 0.90 on the left side.
- There is a vertical line marking the mean (13.9 inches) and another at the value x, which signifies the 90th percentile.
3. **Calculation:**
- Use the Z-score formula:
\[ x = \mu + (z \cdot \sigma) \]
- Find z that corresponds to the shaded area of 0.9000.
- For Z = 1.28 (rounded to two decimal places).
**Conclusion:**
By substituting the known values into the formula:
\[ x = 13.9 + (1.28 \cdot 0.8) \]
\[ x = 13.9 + 1.024 \]
\[ x = 14.924 \]
Thus, the hip breadth separating the smallest 90% from the largest 10% of men is approximately 14.
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