engineer built the circuit depicted in the figure. Assuming E = 12.0 V 4.00 2 2.00 N a R
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Q: An engineer built the circuit depicted in the figure. Assuming E-8.00 V and R=4.70 Q, find the…
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Q: In the figure R1 = 130 N, R2 = R3 = 48.0 0, R4 = 102 0, and the ideal battery has emf e = 6.00…
A: R1=130 ohm R2=R3=48 ohm R4= 102 ohm E= 6volts
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- An engineer built the circuit depicted in the figure. Assuming & = 7.60 V and R = 4.70 , find the following quantities. 12.0 V + a E + Need Help? ㅏ 2.00 Ω www = -3.8453 www 4.00 Ω ww R (a) the current in the 2.00 resistor (Enter the magnitude in mA.) 718.232 mA Read It (b) the potential difference (in V) between points a and b Vb - Va= X Apply Ohm's law and your result from part (a) to calculate your answer. It might help to redraw the circuit so that points a and b are clearly defined junctions. V b(a) What is the resistance (in kΩ) of a 7.00 ✕ 102 Ω, a 2.70 kΩ, and 5.00 kΩ resistor connected in series? kΩ (b) What is the resistance (in Ω) of a 7.00 ✕ 102 Ω, a 2.70 kΩ, and 5.00 kΩ resistor connected in parallel? ΩWhat are the expected readings of the following in the figure below? (R = 9.10 Q, AV = 6.20 V) A R Δν 10.0 N + V 5.00 N + 4.50 V (a) ideal ammeter (Give your answer in mA.) (b) ideal voltmeter (Give your answer in volts.) V (c) What If? How would the readings in the ammeter (in mA) and voltmeter (in volts) change if the 4.50 V battery was flipped so that its positive terminal was to the right? ideal ammeter ideal voltmeter V
- I have posted the question below :) thank you· (a) In the figure, determine the potential difference Vad. (b) If a battery with emf 9.30 V and internal resistance of 1.00 ohm is inserted in the circuit at d, with its negative terminal connected to the negative terminal of the 8.00- V battery. What is now the potential difference Vbc? 0.50 2 4.00 V 9.00 N 6.00 Ω 0.50 N 8.00 V ww 8.00 ΩProblem 5: A current of I- 2.6 A passes through the circuit shown, where R- 65 3R 5R V) 2R 6R 2R 7R 5R 10R Otheexpertta.com Part (a) In terms of R, I, and numeric values, write an expression for the voltage of the · source, V. Part (b) What is the voltage, V in volts? tan( sin() cotanO a acos cosh0t cosO asin() acotan 4 5 6 sinh() cotanhO *1 23 0 tanh0c O Degrees O Radians CLEAR BACKSPACE
- For the circuit shown in the figure, calculate the following. (Assume E = 7.56 V and R 5.40 N.) 12.0 V + 4.00 N 2.00 Ω R (a) the current in the 2.00-n resistor (Enter the magnitude.) A (b) the potential difference between points a and b, AV = V, - V, VA capacitor of capacitance C= 10 µF is connected to a resistance R = 2 2 and a battery of emf E= 5 V of negligible internal resistance. After 20 µs of completing the circuit, find C HH R WW E (a) power delivered by the battery (b) power dissipated as heat (c) rate of energy stored in the capacitorure Find (a) the equivalent resistance of the circuit in Fig- (b) the potential difference across each resistor, (c) each current indicated in Figure and (d) the power delivered to each resistor. Is 15.0 V b 4, www 6.00 Ω 6.00 Ω ww 6.00 Ω d 2.40 Ω 6.00 Ω W 9.00 Ω