Energy transfers by heat through the exterior walls and roof of a house at a rate of 4.06 x 103 J/s = 4.06 kW when the inter temperature is 22.0°C and the outside temperature is -4.00°C. (a) Calculate the electric power required to maintain the interior temperature at 22.0°C if the power is used in electri resistance heaters that convert all the energy transferred in by electrical transmission into internal energy. kW (b) Calculate the electric power required to maintain the interior temperature at 22.0°C if the power is used to drive electric motor that operates the compressor of a heat pump that has a coefficient of performance equal to 60.0% of Carnot-cycle value.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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**Energy Transfer and Electric Power Calculation in a House**

Energy transfers by heat through the exterior walls and roof of a house at a rate of \(4.06 \times 10^3 \, \text{J/s} = 4.06 \, \text{kW}\) when the interior temperature is \(22.0^\circ\text{C}\) and the outside temperature is \(-4.00^\circ\text{C}\).

**Problem Statement:**

(a) **Calculation of Electric Power for Resistance Heaters:**
Calculate the electric power required to maintain the interior temperature at \(22.0^\circ\text{C}\) if the power is used in electric resistance heaters that convert all the energy transferred in by electrical transmission into internal energy.
\[ \_\_\_\_\_\_\_\_ \text{kW} \]

(b) **Calculation of Electric Power for Heat Pump:**
Calculate the electric power required to maintain the interior temperature at \(22.0^\circ\text{C}\) if the power is used to drive an electric motor that operates the compressor of a heat pump that has a coefficient of performance equal to \(60.0\%\) of the Carnot-cycle value.
\[ \_\_\_\_\_\_\_\_ \text{W} \]

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Transcribed Image Text:**Energy Transfer and Electric Power Calculation in a House** Energy transfers by heat through the exterior walls and roof of a house at a rate of \(4.06 \times 10^3 \, \text{J/s} = 4.06 \, \text{kW}\) when the interior temperature is \(22.0^\circ\text{C}\) and the outside temperature is \(-4.00^\circ\text{C}\). **Problem Statement:** (a) **Calculation of Electric Power for Resistance Heaters:** Calculate the electric power required to maintain the interior temperature at \(22.0^\circ\text{C}\) if the power is used in electric resistance heaters that convert all the energy transferred in by electrical transmission into internal energy. \[ \_\_\_\_\_\_\_\_ \text{kW} \] (b) **Calculation of Electric Power for Heat Pump:** Calculate the electric power required to maintain the interior temperature at \(22.0^\circ\text{C}\) if the power is used to drive an electric motor that operates the compressor of a heat pump that has a coefficient of performance equal to \(60.0\%\) of the Carnot-cycle value. \[ \_\_\_\_\_\_\_\_ \text{W} \] **Need Help?** - **Read It** - **Master It** *[Buttons for further assistance]*
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