HDD-Glucose, open chainSTEP 4 O+ H0ene-diolate ionH-STEP 5 ноene-diolate ionOHSTEP 5hydride product ofSTEP 5glycosulose fomHOCHHO-BLUE, MB*CH,hydroperoxide ionSTEP 6-bSTEP 6-aHydroperoxide ionproduct of STEP6-bCHH--OHCHCH,H--HO-COLORLESS, MBHGlycosulose product ofSTEP 5STEP 7|ii.[2] Because the ene-diolate form let go of a hydride, was it reduced or oxidized?

Removal of hydrogen from a molecule is known as oxidation.

Answered: ene-diolate lon STEP 5 glycosulose form

Science

Chemistry

ene-diolate lon STEP 5 glycosulose form

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

HD
D-Glucose, open chain
STEP 4 O
+ H0
ene-diolate ion
H-
STEP 5

но
ene-diolate ion
OH
STEP 5
hydride product of
STEP 5
glycosulose fom
HO
CH
HO-
BLUE, MB*
CH,
hydroperoxide ion
STEP 6-b
STEP 6-a
Hydroperoxide ion
product of STEP
6-b
CH
H-
-OH
CH
CH,
H-
-HO-
COLORLESS, MBH
Glycosulose product of
STEP 5
STEP 7
|
ii.
[2] Because the ene-diolate form let go of a hydride, was it reduced or oxidized?

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