en finals. He randomly selects a sample of 30 Wimbledon finals and 32 French Open finals. The summary statistics are given in the table below in lions of viewers. Grand Slam Final Mean Number of Viewers Standard Deviation Population 1: Wimbledon 21.52 4.665 Population 2: French Open 20.89 3.883
en finals. He randomly selects a sample of 30 Wimbledon finals and 32 French Open finals. The summary statistics are given in the table below in lions of viewers. Grand Slam Final Mean Number of Viewers Standard Deviation Population 1: Wimbledon 21.52 4.665 Population 2: French Open 20.89 3.883
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
100%

Transcribed Image Text:Grand Slam
An ESPN reporter wants to use statistical inference to determine if the average viewership of Wimbledon finals is higher than the French
Open finals. He randomly selects a sample of 30 Wimbledon finals and 32 French Open finals. The summary statistics are given in the table below in
millions of viewers.
Grand Slam Final
Mean Number of Viewers
Standard Deviation
Population 1: Wimbledon
21.52
4.665
Population 2: French Open
20.89
3.883

Transcribed Image Text:4. Calculate the appropriate test statistic.
5. Calculate the p-value using 56.577999 degrees of freedom.
p-value =
6. Based on the above p-value, we have ?
v evidence against the null hypothesis.
7. Use the data to construct a 99% confidence interval for the true difference, µi – µ2:
).
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