Can you please explain where the critical value and rejection region came from? I attached the question as well. I just need an understanding of where the critical value and rejection came from, please break it down for me because I can't figure it out, thanks.I circled it in blue 6.34P.365put last!μ = $50,994n = 200X=¹52588X =51,756+153,4702m = 1.96 (0/1200) = 52 588 - 51756 = 832832 (1200)/196= $6003.19→ =Since CI = (51,756.) $53, 420)2=.05=1-C=1-.95 ⇒ it correspondsH₂:μ = $50,994H₁:μ #50,994=6003.19Assumptions:SRS - no idea, so stated & and p-value may be wronganormal population - no idea, but with n=200 > 30, ils robust.I and p-value may be wrongJ known - ? again,25}1025TS52588-50994.6003,21/√√200-1.9601.960 3.75p-value = 2 P(Z > 3,75) = 2(,0001) = .0002= 3.75Since z = 3.75 is in the RR and the p-value = .0002 < 2 = 105,reject H₂. This is strong evidence that the mean startingsalary at your institution is different from the nationalaverage of $50,994 6.12 Average starting salary. The National Association of Colleges andEmployers (NACE) Summer Salary Survey shows that the current class of collegegraduates received an average starting-salary offer of $50,994.¹0 Your institutioncollected an SRS(n = 200) of its recent graduates and obtained a 95% confidenceinterval of ($51,756, $53,420). What can we conclude about the difference betweenthe average starting salary of recent graduates at your institution and the overallNACE average? Write a short summary.

In this case, the associated confidence level is 95%. The objective is to obtain the z-critical…

Employers (NACE) Summer Salary Survey shows that the current class of college graduates received an average starting-salary offer of $50,994.¹0 Your institution collected an SRS(n = 200) of its recent graduates and obtained a 95% confidence interval of ($51,756, $53,420). What can we conclude about the difference between the average starting salary of recent graduates at your institution and the overall NACE average? Write a short summary.

Employers (NACE) Summer Salary Survey shows that the current class of college graduates received an average starting-salary offer of $50,994.¹0 Your institution collected an SRS(n = 200) of its recent graduates and obtained a 95% confidence interval of ($51,756, $53,420). What can we conclude about the difference between the average starting salary of recent graduates at your institution and the overall NACE average? Write a short summary.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

Can you please explain where the critical value and rejection region came from? I attached the question as well. I just need an understanding of where the critical value and rejection came from, please break it down for me because I can't figure it out, thanks.

I circled it in blue

6.34
P.365
put last!
μ = $50,994
n = 200
X=¹52588
X =
51,756+153,470
2
m = 1.96 (0/1200) = 52 588 - 51756 = 832
832 (1200)/196
= $6003.19
→ =
Since CI = (51,756.) $53, 420)
2=.05=1-C=1-.95 ⇒ it corresponds
H₂:μ = $50,994
H₁:μ #50,994
=6003.19
Assumptions:
SRS - no idea, so stated & and p-value may be wrong
a
normal population - no idea, but with n=200 > 30, ils robust.
I and p-value may be wrong
J known - ? again,
25
}
1025
TS
52588-50994.
6003,21/√√200
-1.960
1.960 3.75
p-value = 2 P(Z > 3,75) = 2(,0001) = .0002
= 3.75
Since z = 3.75 is in the RR and the p-value = .0002 < 2 = 105,
reject H₂. This is strong evidence that the mean starting
salary at your institution is different from the national
average of $50,994

6.12 Average starting salary. The National Association of Colleges and
Employers (NACE) Summer Salary Survey shows that the current class of college
graduates received an average starting-salary offer of $50,994.¹0 Your institution
collected an SRS(n = 200) of its recent graduates and obtained a 95% confidence
interval of ($51,756, $53,420). What can we conclude about the difference between
the average starting salary of recent graduates at your institution and the overall
NACE average? Write a short summary.

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