Employee Absences A store manager wishes to see if the number of absences of her employees is the same for each weekday. She selected a random week and finds the following number of absences. At α=0.10, is there a difference in the number of absences for each day of the week? Use the critical-value method with tables. Day Absences Mon 11 Tues 9 Weds 18 Thurs 23 Fri 24   Identify the claim with the correct hypothesis.   H0: Employee absences are equally distributed over the five-day workweek. claim/not claim▼(Choose one) H1: Employee absences are not equally distributed over the five-day workweek. claim/not claim ▼(Choose one) Find the critical value. Round the answer to at least three decimal places. The critical value is Compute the test value. Round the intermediate and final answer to at least three decimal places.   X2= Make the decision.   reject/do not reject▼(Choose one) the null hypothesis.         Summarize the results.   There is/is not ▼(Choose one) that the employee absences are not equally distributed over the five-day workweek.

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Employee Absences A store manager wishes to see if the number of absences of her employees is the same for each weekday. She selected a random week and finds the following number of absences. At α=0.10, is there a difference in the number of absences for each day of the week? Use the critical-value method with tables.

Day Absences
Mon
11
Tues
9
Weds
18
Thurs
23
Fri
24

 

Identify the claim with the correct hypothesis.

 

H0: Employee absences are equally distributed over the five-day workweek. claim/not claim▼(Choose one)
H1: Employee absences are not equally distributed over the five-day workweek. claim/not claim ▼(Choose one)

Find the critical value. Round the answer to at least three decimal places.

The critical value is

Compute the test value. Round the intermediate and final answer to at least three decimal places.

 
X2=

Make the decision.

 

reject/do not reject▼(Choose one) the null hypothesis.
 
 
 

 

Summarize the results.

 

There is/is not ▼(Choose one) that the employee absences are not equally distributed over the five-day workweek.
 
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