Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question:**
If you expect a chemical reaction to produce 4.38 L of oxygen gas at 19°C and 101 kPa, what will be the volume at 25°C and 98 kPa?
**Explanation:**
This problem involves using the Ideal Gas Law and the combined gas law formula to determine the change in volume of a gas under different conditions of temperature and pressure.
**Solution Approach:**
The combined gas law is:
\[ \frac{P_1 \times V_1}{T_1} = \frac{P_2 \times V_2}{T_2} \]
Where:
- \( P_1 \), \( V_1 \), \( T_1 \) are the initial pressure, volume, and temperature.
- \( P_2 \), \( V_2 \), \( T_2 \) are the final pressure, volume, and temperature.
- Temperatures need to be in Kelvin, so convert: \( T(K) = T(°C) + 273.15 \).
1. Convert the temperatures from Celsius to Kelvin.
- Initial temperature (\( T_1 \)): \( 19°C + 273.15 = 292.15 \, K \)
- Final temperature (\( T_2 \)): \( 25°C + 273.15 = 298.15 \, K \)
2. Substitute the given values into the combined gas law and solve for the unknown volume \( V_2 \):
\[ \frac{101 \, \text{kPa} \times 4.38 \, \text{L}}{292.15 \, \text{K}} = \frac{98 \, \text{kPa} \times V_2}{298.15 \, \text{K}} \]
Solve for \( V_2 \):
\[ V_2 = \frac{101 \times 4.38 \times 298.15}{98 \times 292.15} \]
Calculate \( V_2 \) to find the solution.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F78a96f4b-c4a7-4e44-95dd-3606c481f172%2F25a5c6b4-3726-4dff-99a0-a358b4de8a73%2Fp81z7k8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question:**
If you expect a chemical reaction to produce 4.38 L of oxygen gas at 19°C and 101 kPa, what will be the volume at 25°C and 98 kPa?
**Explanation:**
This problem involves using the Ideal Gas Law and the combined gas law formula to determine the change in volume of a gas under different conditions of temperature and pressure.
**Solution Approach:**
The combined gas law is:
\[ \frac{P_1 \times V_1}{T_1} = \frac{P_2 \times V_2}{T_2} \]
Where:
- \( P_1 \), \( V_1 \), \( T_1 \) are the initial pressure, volume, and temperature.
- \( P_2 \), \( V_2 \), \( T_2 \) are the final pressure, volume, and temperature.
- Temperatures need to be in Kelvin, so convert: \( T(K) = T(°C) + 273.15 \).
1. Convert the temperatures from Celsius to Kelvin.
- Initial temperature (\( T_1 \)): \( 19°C + 273.15 = 292.15 \, K \)
- Final temperature (\( T_2 \)): \( 25°C + 273.15 = 298.15 \, K \)
2. Substitute the given values into the combined gas law and solve for the unknown volume \( V_2 \):
\[ \frac{101 \, \text{kPa} \times 4.38 \, \text{L}}{292.15 \, \text{K}} = \frac{98 \, \text{kPa} \times V_2}{298.15 \, \text{K}} \]
Solve for \( V_2 \):
\[ V_2 = \frac{101 \times 4.38 \times 298.15}{98 \times 292.15} \]
Calculate \( V_2 \) to find the solution.
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