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ement from the box. The probability that the third red ball is the seventh ball drawn is. balls and 5 black balls. Balls are drawn randomly one at a time with a. 0.169 b.0.282 c. 0.179 d. 0.121 e. None 5. A box contains 20 balls, 13 of them are red and the rest are blue. Three balls are drawn randomly without replacement. The probability of getting at least 1 blue ball is. a) 0.749 b) 0.251 c) 0.479 d) 0521 6. The moment generating function of a random variable Y Then PC a. 04 0.976 e. None e) none

ement from the box. The probability that the third red ball is the seventh ball drawn is. balls and 5 black balls. Balls are drawn randomly one at a time with a. 0.169 b.0.282 c. 0.179 d. 0.121 e. None 5. A box contains 20 balls, 13 of them are red and the rest are blue. Three balls are drawn randomly without replacement. The probability of getting at least 1 blue ball is. a) 0.749 b) 0.251 c) 0.479 d) 0521 6. The moment generating function of a random variable Y Then PC a. 04 0.976 e. None e) none

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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pleaseeeee solve question 5, quickly please 

2. How many different four-digit numbers can be formed from the digits 1,2,3,4,5,6,7 such that the first digit 3 or 6 also you cannot repeat the digit a. 240 b.48 c. 120 P(A) 3. If A, B and C are mutually independent events and that P(A) = 0.3, P(B) = 0.2, P(C) = 0.4. The probability that at least one of the events occur is a. 0.336 b.0.664 c. 0.024 a. 0.4 4. A box contains 3 red balls and 5 black balls. Balls are drawn randomly one at a time with replacement from the box. The probability that the third red ball is the seventh ball drawn is. a. 0.169 b.0.282 c. 0.179 d. 0.121 e. None 5. A box contains 20 balls, 13 of them are red and the rest are blue. Three balls are drawn randomly without replacement. The probability of getting at least 1 blue ball is. a) 0.749 b) 0.251 c) 0.479 d) 0521 b. 0.7 c. 0.9 6. The moment generating function of a random variable X M(t) = 0.5 +0.2e+0.2e³ +0.1e³t Then P(-1.5<X<3.4)= d. e-1 7. If the random variable X has a chi-square distribution with degrees of freedom r, and if E(SX+3)=33. find var (X) a. 3.46 b.12 d. 24 c. 36 d. 0.976 d. 6 ve that X has an exponential distribution. If Var (4-4- 20 b.0 0.5 e. None e. None 8. Let X have a negative binomial distribution with rand P=0.6. If the mean of X is 5 then requal b. 0.83 a. 1.8 c. 3 d.9 e. None =20 e) none e. None e. None
Transcribed Image Text:2. How many different four-digit numbers can be formed from the digits 1,2,3,4,5,6,7 such that the first digit 3 or 6 also you cannot repeat the digit a. 240 b.48 c. 120 P(A) 3. If A, B and C are mutually independent events and that P(A) = 0.3, P(B) = 0.2, P(C) = 0.4. The probability that at least one of the events occur is a. 0.336 b.0.664 c. 0.024 a. 0.4 4. A box contains 3 red balls and 5 black balls. Balls are drawn randomly one at a time with replacement from the box. The probability that the third red ball is the seventh ball drawn is. a. 0.169 b.0.282 c. 0.179 d. 0.121 e. None 5. A box contains 20 balls, 13 of them are red and the rest are blue. Three balls are drawn randomly without replacement. The probability of getting at least 1 blue ball is. a) 0.749 b) 0.251 c) 0.479 d) 0521 b. 0.7 c. 0.9 6. The moment generating function of a random variable X M(t) = 0.5 +0.2e+0.2e³ +0.1e³t Then P(-1.5<X<3.4)= d. e-1 7. If the random variable X has a chi-square distribution with degrees of freedom r, and if E(SX+3)=33. find var (X) a. 3.46 b.12 d. 24 c. 36 d. 0.976 d. 6 ve that X has an exponential distribution. If Var (4-4- 20 b.0 0.5 e. None e. None 8. Let X have a negative binomial distribution with rand P=0.6. If the mean of X is 5 then requal b. 0.83 a. 1.8 c. 3 d.9 e. None =20 e) none e. None e. None
Expert Solution
Step 1

It is given that 

Red balls = 13

Blue balls = 7

Total balls = 20

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