Ement 15: Colligative Properties Experiment 15: Colligative Properties 7. Solution preparation: a. How many grams of NaCl will you need to prepare 50.0 mL of 1.00M NaCI? b. How many grams of NaCl will you need to prepare 50.0 mL of 3.00M NaCl? c. How many grams of glycerol will you need to prepare 50.0 mL of 1.00M glycerol (C3H3O3)? d. How many grams of glycerol will you need to prepare 50.0 mL of 3.00M glycerol (C3H$O3)?
Ement 15: Colligative Properties Experiment 15: Colligative Properties 7. Solution preparation: a. How many grams of NaCl will you need to prepare 50.0 mL of 1.00M NaCI? b. How many grams of NaCl will you need to prepare 50.0 mL of 3.00M NaCl? c. How many grams of glycerol will you need to prepare 50.0 mL of 1.00M glycerol (C3H3O3)? d. How many grams of glycerol will you need to prepare 50.0 mL of 3.00M glycerol (C3H$O3)?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Stoichiometry is mainly based on the calculation of moles and volumes. These two values are used to calculate the molarity of solution. The relation between moles, and mass with molarity is as given below;
Step 3
Part (a)
Volume – 50 mL = 50 x 10-3 L
Molarity = 1.00 M
Molar mass of NaCl = 58.5 g/mol
Substitute the values to calculate mass:
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