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ƏM ƏN ду дх exact differential equation, we multiply eq. 1 by 1 where ƏM ƏN dy¯əx N = f(x) then a= eS (x) dx

ƏM ƏN ду дх exact differential equation, we multiply eq. 1 by 1 where ƏM ƏN dy¯əx N = f(x) then a= eS (x) dx

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Determination of Integrating Factor (Reduction to Exact Differential Equation) Considering the equation M(x,y)dx + N(x, y) = 0 -------- eq.1 If, ƏM aN dy " əx To reduce eqn. 1 to an exact differential equation, we multiply eq. 1 by a where a is an integrating factor. Integrating Factors: If ƏM ƏN dyəx = f(x) then a = eS S(x) dx If aM ƏN ду ax M g(y) then A= e-S9v) dy
Transcribed Image Text:Determination of Integrating Factor (Reduction to Exact Differential Equation) Considering the equation M(x,y)dx + N(x, y) = 0 -------- eq.1 If, ƏM aN dy " əx To reduce eqn. 1 to an exact differential equation, we multiply eq. 1 by a where a is an integrating factor. Integrating Factors: If ƏM ƏN dyəx = f(x) then a = eS S(x) dx If aM ƏN ду ax M g(y) then A= e-S9v) dy
Reduction to Exact Differential Equation 3 (x² + 3y2 + 6y)dy +-(x² + y²)dx = 0
Transcribed Image Text:Reduction to Exact Differential Equation 3 (x² + 3y2 + 6y)dy +-(x² + y²)dx = 0
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