Eliminate the parameter and describe the shape of the curve: :=√√x+4; _y=3√t; for 0≤t≤16

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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**Eliminate the parameter and describe the shape of the curve:**

Given the parametric equations:
\[ x = \sqrt{t} + 4, \quad y = 3\sqrt{t} \]
for \[ 0 \leq t \leq 16 \]. 

To eliminate the parameter \( t \), we solve for \( t \) in terms of \( x \) or \( y \).

1. From the equation \( x = \sqrt{t} + 4 \):

   \[
   \sqrt{t} = x - 4
   \]

   \[
   t = (x - 4)^2
   \]

2. Substitute \( t \) in the equation for \( y \):

   \[
   y = 3 \sqrt{t} = 3(x - 4)
   \]

Therefore, the Cartesian equation of the curve is:

\[ 
y = 3(x - 4) 
\]

The shape of this curve is a straight line with a slope of 3, offset horizontally by 4 units. The line is defined for the range \( 0 \leq t \leq 16 \), which translates to \( 0 \leq x-4 \leq 4 \), or \( 4 \leq x \leq 8 \). 

The corresponding range for \( y \) is \( 0 \leq y \leq 12 \).
Transcribed Image Text:**Eliminate the parameter and describe the shape of the curve:** Given the parametric equations: \[ x = \sqrt{t} + 4, \quad y = 3\sqrt{t} \] for \[ 0 \leq t \leq 16 \]. To eliminate the parameter \( t \), we solve for \( t \) in terms of \( x \) or \( y \). 1. From the equation \( x = \sqrt{t} + 4 \): \[ \sqrt{t} = x - 4 \] \[ t = (x - 4)^2 \] 2. Substitute \( t \) in the equation for \( y \): \[ y = 3 \sqrt{t} = 3(x - 4) \] Therefore, the Cartesian equation of the curve is: \[ y = 3(x - 4) \] The shape of this curve is a straight line with a slope of 3, offset horizontally by 4 units. The line is defined for the range \( 0 \leq t \leq 16 \), which translates to \( 0 \leq x-4 \leq 4 \), or \( 4 \leq x \leq 8 \). The corresponding range for \( y \) is \( 0 \leq y \leq 12 \).
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