Elias has a jar of 15 black marbles, 8 red marbles, and 9 white marbles. He will randomly choose a marble, record its color, and replace it in the jar. He will then randomly choose a second marble and record its color. 15/24 What is the probability of choosing a black marble and then a red marble? 9/128 135/1024 15/128

Elementary Geometry For College Students, 7e
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### Probability Exercise: Drawing Marbles

Elias has a jar containing 15 black marbles, 8 red marbles, and 9 white marbles. He will perform the following experiment twice:

1. Randomly choose a marble from the jar.
2. Record its color.
3. Replace the marble back into the jar.

He will then choose a second marble and record its color.

#### Question:
What is the probability of choosing a black marble first and then a red marble on the second draw?

### Answer Options:
- \( \frac{15}{24} \)
- \( \frac{9}{128} \)
- \( \frac{135}{1024} \)
- \( \frac{15}{128} \)

To find the correct answer, it is important to note:
1. The total number of marbles is \( 15 + 8 + 9 = 32 \).
2. The probability of drawing a black marble first is \( \frac{15}{32} \).
3. Since the marble is replaced, the second draw also consists of 32 marbles.
4. The probability of drawing a red marble next is \( \frac{8}{32} \).

Thus, the combined probability:
\[ P(\text{Black, then Red}) = P(\text{Black}) \times P(\text{Red}) \]
\[ P(\text{Black, then Red}) = \frac{15}{32} \times \frac{8}{32} = \frac{120}{1024} = \frac{15}{128} \]

### Final Answer:
\[ P(\text{Black, then Red}) = \frac{15}{128} \]

Hence, the correct option is:
- \( \boxed{\frac{15}{128}} \)
Transcribed Image Text:### Probability Exercise: Drawing Marbles Elias has a jar containing 15 black marbles, 8 red marbles, and 9 white marbles. He will perform the following experiment twice: 1. Randomly choose a marble from the jar. 2. Record its color. 3. Replace the marble back into the jar. He will then choose a second marble and record its color. #### Question: What is the probability of choosing a black marble first and then a red marble on the second draw? ### Answer Options: - \( \frac{15}{24} \) - \( \frac{9}{128} \) - \( \frac{135}{1024} \) - \( \frac{15}{128} \) To find the correct answer, it is important to note: 1. The total number of marbles is \( 15 + 8 + 9 = 32 \). 2. The probability of drawing a black marble first is \( \frac{15}{32} \). 3. Since the marble is replaced, the second draw also consists of 32 marbles. 4. The probability of drawing a red marble next is \( \frac{8}{32} \). Thus, the combined probability: \[ P(\text{Black, then Red}) = P(\text{Black}) \times P(\text{Red}) \] \[ P(\text{Black, then Red}) = \frac{15}{32} \times \frac{8}{32} = \frac{120}{1024} = \frac{15}{128} \] ### Final Answer: \[ P(\text{Black, then Red}) = \frac{15}{128} \] Hence, the correct option is: - \( \boxed{\frac{15}{128}} \)
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