Elementary students are not advisedtouse Facebook at their age.However, Ms. Minchin believes thatstudents in their school are using FB6 hours a week, on the average. Shetook a random sample of 30 Grade 4to 7 students and obtained aninterval estimateof the meannumber of hours spent on FB,[5.309880, 6.210120]. From this, Ms.Minchin can conclude that there isevidence that the mean timespent using FB per week is6hours.no sufficient, equal tosufficient, not equal tono sufficient, not equal tosufficient, equal to

We have given that Ms. Minchin believes that students in their school are using FB 6 hours a week,…

Answered: Elementary students are not advised…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Two suppliers manufacture a plastic gear used in a laser printer. The impact strength of these gears measured in foot-pounds is an important characteristic. A random sample of 10 gears from supplier 1 results in ₁ = 290 and s₁ = 12, and another random sample of 16 gears from the second supplier results in ₂ = 321 and s₂ = 22. Is there evidence to support the claim that supplier 2 provides gears with higher mean impact strength? Use a = 0.05, and assume that both populations are normally distributed but the variances are not equal. O a. Because -4.64 < -1.714, fail to reject the Null Hypothesis Ob. None among the choices O c. Reject the Null Hypothesis Od. Because -4.64 < -1.714, reject the Null Hypothesis
The time to complete the Advanced Placement (AP) Statistics Exam in previous years is normally distributed with an average time of 2.4 hours. Because of school closures due to COVID-19, the College Board offered an at-home test for the 2020 AP Statistics Exam. A teacher feels that students, on average, will have a different completion time for the at-home exam. They take a random sample of 25 students that took the exam and their mean time was 2.74 hours with a standard deviation of 0.25 hours. Test to see if the mean time has significantly changed using a 5% level of significance. Give answers to at least 4 decimal places. What are the correct hypotheses? Ho: M H₁: P Based on the hypotheses, find the following: Test Statistic t = Critical-Value t = ± 2.4 #v 2.4 o hours hours
Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 42 randomly selected people who train in groups and finds that they run a mean of 47.1 miles per week. Assume that the population standard deviation for group runners is known to be 4.4 miles per week. She also interviews a random sample of 47 people who train on their own and finds that they run a mean of 48.5 miles per week. Assume that the population standard deviation for people who run by themselves is 1.8 miles per week. Test the claim at the 0.01 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.
When you get a surprisingly low price on a product do you assume that you got a really good deal or that you bought a low-quality product? Research indicates that you are more likely to associate low price and low quality if someone else makes the purchase rather than yourself. In a similar study, 16 participants were asked to rate the quality of low-priced items under two scenarios: purchased by a friend or purchased yourself. The results produced a mean difference of 2.6 and a SS = 135, with self-purchases rated higher. Is there evidence that the judged quality of objects significantly increase for self-purchases than for purchases made by others? Please use a one-tailed test with level of significance of 5%.
Is narcissism a more common personality trait today than it was a few decades ago? It is known that the mean population score on the Narcissistic Personality Inventory (NPI) for students attending University of South Alabama around 20 years ago was μ= 15 (Twenge, 2010). Interested in the narcissism levels of students in the year 2020, a researcher administers the NPI to a random sample of 25 University of Alabama sophomores this Spring term. The mean NPI score from the researcher’s sample of sophomores is M = 16.5, with s = 3.4. 1. Write the null and alternative hypotheses in symbols. Possible symbols for your answer: H0, H1, μ, M, σ. 2. Calculate the standard error. 3. Find the critical value for the test statistic, assuming alpha = .05 (Use largest [i.e., most conservative] value if exact value not given in the chart) a) 2.064 b) 1.96 c) 1.98 d) 2.000
A new small business wants to know if its current radio advertising is effective. The owners decide to look at the mean number of customers who make a purchase in the store on days immediately following days when the radio ads are played as compared to the mean for those days following days when no radio advertisements are played. They found that for 10 days following no advertisements, the mean was 18.3 purchasing customers with a standard deviation of 1.8 customers. On 7 days following advertising, the mean was 19.4 purchasing customers with a standard deviation of 1.6 customers. Test the claim, at the 0.02 level, that the mean number of customers who make a purchase in the store is lower for days following no advertising compared to days following advertising. Assume that both populations are approximately normal and that the population variances are equal. Let days following no advertisements be Population 1 and let days following advertising be Population 2. Step 3 of 3: Draw a…
Bone mineral density (BMD) is a measure of bone strength. Studies show that BMD declines after age 45. The impact of exercise may increase BMD. A random sample of 59 women between the ages of 41 and 45 with no major health problems were studied. The women were classified into one of two groups based upon their level of exercise activity: walking women and sedentary women. The 39 women who walked regularly had a mean BMD of 5.96 with a standard deviation of 1.22. The 20 women who are sedentary had a mean BMD of 4.41 with a standard deviation of 1.02. Which of the following inference procedures could be used to estimate the difference in the mean BMD for these two types of women
use ms excel, thank you!
A new small business wants to know if its current radio advertising is effective. The owners decide to look at the mean number of customers who make a purchase in the store on days immediately following days when the radio ads are played as compared to the mean for those days following days when no radio advertisements are played. They found that for 13 days following no advertisements, the mean was 23.9 purchasing customers with a standard deviation of 1.9 customers. On 6 days following advertising, the mean was 24.7 purchasing customers with a standard deviation of 1.6 customers. Test the claim, at the 0.01 level, that the mean number of customers who make a purchase in the store is lower for days following no advertising compared to days following advertising. Assume that both populations are approximately normal and that the population variances are equal. Let days following no advertisements be Population 1 and let days following advertising be Population 2. Step 3 of 3: Draw a…
During the busy season, it is important for the shipping manager at ShipMundo to be able to estimate the time it takes the loading crew to load a truck. The shipping manager has found that she can model the load times using a normal distribution with a mean of 152 minutes and a standard deviation of 15 minutes. Use this table or the ALEKS calculator to find the percentage of load times between 116 minutes and 149 minutes according to the model. For your intermediate computations, use four or more decimal places. Give your final answer to two decimal places (for example 98.23%).
A researcher is interested in examining the effect of emotions on those that are convicted of a crime while under the age of 15. She decides to compare the empathy quotient (EQ) scores of those convicted of violent crimes to those convicted of non-violent crimes. A random sample of 35 violent offenders had a mean score of 33.5 and a standard deviation of 3.2, and another sample of 46 non-violent offenders had a mean of 37 and a standard deviation of 3.8. Also, suppose that equal variance cannot be assumed, but the populations are normal. If a higher EQ score indicated increased empathy, construct a 95% confidence interval for the difference in means. What is the critical value? What is the lower bound of the confidence interval? What can she conclude about the difference in empathy between the two groups?

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