elementary step that gives ea 5.41 The reaction of 3-tert-butyl-3-pentanol with hydrochloric acid gave the products shown. Write appropriate equations explaining the formation of each. * OH HCT * CI

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Questing 5.41
**Title: Reaction of 3-tert-butyl-3-pentanol with Hydrochloric Acid**

**Introduction:**

In this example, we explore the reaction of 3-tert-butyl-3-pentanol with hydrochloric acid to produce two different chlorinated products. This reaction demonstrates the process of substitution in organic chemistry.

**Reaction Description:**

The starting material, 3-tert-butyl-3-pentanol, reacts with hydrochloric acid (HCl). During this reaction, the hydroxyl group (OH) in the alcohol is substituted by a chlorine (Cl) atom, resulting in the formation of a chloroalkane. Two different products are formed, which represent different possible results of this substitution reaction.

**Chemical Equations:**

1. The primary reaction: 
   \[
   \text{{3-tert-butyl-3-pentanol}} + \text{{HCl}} \rightarrow \text{{3-tert-butyl-3-chloropentane}}
   \]

2. Alternative product:
   \[
   \text{{3-tert-butyl-2-chloropentane}}
   \]

**Diagram Explanation:**

The diagram illustrates the reaction pathway:
- **Reactant Structure**: The original alcohol compound (showing OH group) is depicted on the left.
- **Reaction Arrow**: HCl is shown above the reaction arrow, indicating that it's the reacting agent.
- **Products**: Two distinct structures of chlorinated compounds are presented on the right, each marked with a Cl atom in place of the original OH group.

**Conclusion:**

The substitution of the hydroxyl group with a chlorine atom in this reaction underlines the principles of nucleophilic substitution. Understanding these mechanisms is critical in organic synthesis and industrial chemistry processes.
Transcribed Image Text:**Title: Reaction of 3-tert-butyl-3-pentanol with Hydrochloric Acid** **Introduction:** In this example, we explore the reaction of 3-tert-butyl-3-pentanol with hydrochloric acid to produce two different chlorinated products. This reaction demonstrates the process of substitution in organic chemistry. **Reaction Description:** The starting material, 3-tert-butyl-3-pentanol, reacts with hydrochloric acid (HCl). During this reaction, the hydroxyl group (OH) in the alcohol is substituted by a chlorine (Cl) atom, resulting in the formation of a chloroalkane. Two different products are formed, which represent different possible results of this substitution reaction. **Chemical Equations:** 1. The primary reaction: \[ \text{{3-tert-butyl-3-pentanol}} + \text{{HCl}} \rightarrow \text{{3-tert-butyl-3-chloropentane}} \] 2. Alternative product: \[ \text{{3-tert-butyl-2-chloropentane}} \] **Diagram Explanation:** The diagram illustrates the reaction pathway: - **Reactant Structure**: The original alcohol compound (showing OH group) is depicted on the left. - **Reaction Arrow**: HCl is shown above the reaction arrow, indicating that it's the reacting agent. - **Products**: Two distinct structures of chlorinated compounds are presented on the right, each marked with a Cl atom in place of the original OH group. **Conclusion:** The substitution of the hydroxyl group with a chlorine atom in this reaction underlines the principles of nucleophilic substitution. Understanding these mechanisms is critical in organic synthesis and industrial chemistry processes.
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