Electrostatic precipitators use electric forces to remove pollutant particles from smoke, in particular in the smokestacks of coal-burning power plants. One form of precipitator consists of a vertical, hollow, metal cylinder with a thin wire, insulated from the cylinder, running along its axis (Figure 1). A large potential difference is established between the wire and the outer cylinder, with the wire at lower potential. This sets up a strong radial electric field directed inward. The field produces a region of ionized air near the wire. Smoke enters the precipitator at the bottom, ash and dust in it pick up electrons, and the charged pollutants are accelerated toward the outer cylinder wall by the electric field. Suppose the radius of the central wire is 90.0 um, the radius of the cylinder is 14.0 cm, and a potential difference of 50.0 kV is established between the wire and the cylinder. Also assume that the wire and cylinder are both very long in comparison to the cylinder radius. Part A What is the magnitude of the electric field midway between the wire and the cylinder wall? Express your answer in volts per meter. E = V/m Submit Request Answer Part B What magnitude of charge must a 25.5 ug ash particle have if the electric field computed in part A is to exert a force ten times the weight of the particle? Express your answer in coulombs. igure < 1 of 1> C Submit Reguest Answer 14.0 cm Provide Feedback Power source 50.0 kV Air flow
Electrostatic precipitators use electric forces to remove pollutant particles from smoke, in particular in the smokestacks of coal-burning power plants. One form of precipitator consists of a vertical, hollow, metal cylinder with a thin wire, insulated from the cylinder, running along its axis (Figure 1). A large potential difference is established between the wire and the outer cylinder, with the wire at lower potential. This sets up a strong radial electric field directed inward. The field produces a region of ionized air near the wire. Smoke enters the precipitator at the bottom, ash and dust in it pick up electrons, and the charged pollutants are accelerated toward the outer cylinder wall by the electric field. Suppose the radius of the central wire is 90.0 um, the radius of the cylinder is 14.0 cm, and a potential difference of 50.0 kV is established between the wire and the cylinder. Also assume that the wire and cylinder are both very long in comparison to the cylinder radius. Part A What is the magnitude of the electric field midway between the wire and the cylinder wall? Express your answer in volts per meter. E = V/m Submit Request Answer Part B What magnitude of charge must a 25.5 ug ash particle have if the electric field computed in part A is to exert a force ten times the weight of the particle? Express your answer in coulombs. igure < 1 of 1> C Submit Reguest Answer 14.0 cm Provide Feedback Power source 50.0 kV Air flow
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Transcribed Image Text:Electrostatic precipitators use electric forces to remove pollutant particles from smoke, in
particular in the smokestacks of coal-burning power plants. One form of precipitator
consists of a vertical, hollow, metal cylinder with a thin wire, insulated from the cylinder,
running along its axis (Figure 1). A large potential difference is established between the
wire and the outer cylinder, with the wire at lower potential. This sets up a strong radial
electric field directed inward. The field produces a region of ionized air near the wire.
Smoke enters the precipitator at the bottom, ash and dust in it pick up electrons, and the
charged pollutants are accelerated toward the outer cylinder wall by the electric field.
Suppose the radius of the central wire is 90.0 pm, the radius of the cylinder is
14.0 cm, and a potential difference of 50.0 kV is established between the wire and the
cylinder. Also assume that the wire and cylinder are both very long in comparison to the
cylinder radius.
Part A
What is the magnitude of the electric field midway between the wire and the cylinder wall?
Express your answer in volts per meter.
?
E =
V/m
Submit
Request Answer
Part B
What magnitude of charge must a 25.5 ug ash particle have if the electric field computed in part A is to exert a force ten times the weight of the particle?
Express your answer in coulombs.
Πνα ΑΣφ
Figure
1 of 1
q =
Submit
Request Answer
14.0 cm
Provide Feedback
Power source
50.0 kV
Air flow
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