Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter6: Electronic Structure And Periodic Properties Of Elements
Section: Chapter Questions
Problem 14E: Answer the following questions about a Blu-ray laser: (a) The laser on a Blu-ray player has a...
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Question
![**Understanding Electromagnetic Radiation and Light**
**Problem Statement:**
Electromagnetic radiation with a wavelength of 695 nm appears as orange light to the human eye. The frequency of this light is ____ s⁻¹.
**Explanation:**
To find the frequency (f) of the electromagnetic radiation, which appears as orange light, you can use the relationship between the speed of light (c), wavelength (λ), and frequency (f). The equation is given by:
\[ c = λf \]
Where:
- \( c \) is the speed of light in a vacuum (approximately \( 3.00 \times 10^8 \) meters per second)
- \( λ \) is the wavelength in meters
- \( f \) is the frequency in Hertz (Hz)
1. **Convert Wavelength to Meters:**
Given \( λ = 695 \) nm (nanometers),
\[ 1 \text{ nm} = 10^{-9} \text{ meters} \]
So,
\[ λ = 695 \times 10^{-9} \text{ meters} \]
2. **Rearrange the Equation:**
To find the frequency, we rearrange the equation to:
\[ f = \dfrac{c}{λ} \]
3. **Calculate the Frequency:**
Substitute the known values into the equation:
\[ f = \dfrac{3.00 \times 10^8 \text{ meters/second}}{695 \times 10^{-9} \text{ meters}} \]
Simplify to get the frequency.
**Interactive Box:**
\[ \boxed{f = \dfrac{3.00 \times 10^8}{695 \times 10^{-9}} \text{ s}^{-1}} \]
By solving for \( f \), you can determine the frequency of the orange light in Hz.
---
This section provides a step-by-step approach to solving the problem and understanding the concepts related to electromagnetic radiation and light frequency. It includes both explanations and the calculation method necessary for arriving at the answer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7b0fedb7-adbc-492c-aa14-9f5d12342848%2F35701108-7d79-4e5d-8211-69a2cb1705db%2F1p12v6d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Understanding Electromagnetic Radiation and Light**
**Problem Statement:**
Electromagnetic radiation with a wavelength of 695 nm appears as orange light to the human eye. The frequency of this light is ____ s⁻¹.
**Explanation:**
To find the frequency (f) of the electromagnetic radiation, which appears as orange light, you can use the relationship between the speed of light (c), wavelength (λ), and frequency (f). The equation is given by:
\[ c = λf \]
Where:
- \( c \) is the speed of light in a vacuum (approximately \( 3.00 \times 10^8 \) meters per second)
- \( λ \) is the wavelength in meters
- \( f \) is the frequency in Hertz (Hz)
1. **Convert Wavelength to Meters:**
Given \( λ = 695 \) nm (nanometers),
\[ 1 \text{ nm} = 10^{-9} \text{ meters} \]
So,
\[ λ = 695 \times 10^{-9} \text{ meters} \]
2. **Rearrange the Equation:**
To find the frequency, we rearrange the equation to:
\[ f = \dfrac{c}{λ} \]
3. **Calculate the Frequency:**
Substitute the known values into the equation:
\[ f = \dfrac{3.00 \times 10^8 \text{ meters/second}}{695 \times 10^{-9} \text{ meters}} \]
Simplify to get the frequency.
**Interactive Box:**
\[ \boxed{f = \dfrac{3.00 \times 10^8}{695 \times 10^{-9}} \text{ s}^{-1}} \]
By solving for \( f \), you can determine the frequency of the orange light in Hz.
---
This section provides a step-by-step approach to solving the problem and understanding the concepts related to electromagnetic radiation and light frequency. It includes both explanations and the calculation method necessary for arriving at the answer.
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