Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![**Understanding Electromagnetic Radiation and Light**
**Problem Statement:**
Electromagnetic radiation with a wavelength of 695 nm appears as orange light to the human eye. The frequency of this light is ____ s⁻¹.
**Explanation:**
To find the frequency (f) of the electromagnetic radiation, which appears as orange light, you can use the relationship between the speed of light (c), wavelength (λ), and frequency (f). The equation is given by:
\[ c = λf \]
Where:
- \( c \) is the speed of light in a vacuum (approximately \( 3.00 \times 10^8 \) meters per second)
- \( λ \) is the wavelength in meters
- \( f \) is the frequency in Hertz (Hz)
1. **Convert Wavelength to Meters:**
Given \( λ = 695 \) nm (nanometers),
\[ 1 \text{ nm} = 10^{-9} \text{ meters} \]
So,
\[ λ = 695 \times 10^{-9} \text{ meters} \]
2. **Rearrange the Equation:**
To find the frequency, we rearrange the equation to:
\[ f = \dfrac{c}{λ} \]
3. **Calculate the Frequency:**
Substitute the known values into the equation:
\[ f = \dfrac{3.00 \times 10^8 \text{ meters/second}}{695 \times 10^{-9} \text{ meters}} \]
Simplify to get the frequency.
**Interactive Box:**
\[ \boxed{f = \dfrac{3.00 \times 10^8}{695 \times 10^{-9}} \text{ s}^{-1}} \]
By solving for \( f \), you can determine the frequency of the orange light in Hz.
---
This section provides a step-by-step approach to solving the problem and understanding the concepts related to electromagnetic radiation and light frequency. It includes both explanations and the calculation method necessary for arriving at the answer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7b0fedb7-adbc-492c-aa14-9f5d12342848%2F35701108-7d79-4e5d-8211-69a2cb1705db%2F1p12v6d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Understanding Electromagnetic Radiation and Light**
**Problem Statement:**
Electromagnetic radiation with a wavelength of 695 nm appears as orange light to the human eye. The frequency of this light is ____ s⁻¹.
**Explanation:**
To find the frequency (f) of the electromagnetic radiation, which appears as orange light, you can use the relationship between the speed of light (c), wavelength (λ), and frequency (f). The equation is given by:
\[ c = λf \]
Where:
- \( c \) is the speed of light in a vacuum (approximately \( 3.00 \times 10^8 \) meters per second)
- \( λ \) is the wavelength in meters
- \( f \) is the frequency in Hertz (Hz)
1. **Convert Wavelength to Meters:**
Given \( λ = 695 \) nm (nanometers),
\[ 1 \text{ nm} = 10^{-9} \text{ meters} \]
So,
\[ λ = 695 \times 10^{-9} \text{ meters} \]
2. **Rearrange the Equation:**
To find the frequency, we rearrange the equation to:
\[ f = \dfrac{c}{λ} \]
3. **Calculate the Frequency:**
Substitute the known values into the equation:
\[ f = \dfrac{3.00 \times 10^8 \text{ meters/second}}{695 \times 10^{-9} \text{ meters}} \]
Simplify to get the frequency.
**Interactive Box:**
\[ \boxed{f = \dfrac{3.00 \times 10^8}{695 \times 10^{-9}} \text{ s}^{-1}} \]
By solving for \( f \), you can determine the frequency of the orange light in Hz.
---
This section provides a step-by-step approach to solving the problem and understanding the concepts related to electromagnetic radiation and light frequency. It includes both explanations and the calculation method necessary for arriving at the answer.
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