Electrode 1 Cu Cu Cu Cu Zn Zn Zn Pb Pb Mg Electrode 2 Zn Pb Mg Sn Pb Mg Sn Mg Sn Sn Cell potential Ecell in V 0 O 0.9% Zn Сн 0401 v Pb Cu Cu 1o 480 mg •363 Sn 515 20 G Anode 692 482 2n Mg Bo 10121 Cathode + Ecell = Ecathode - E anode Cu рь 2n Sn рь 16-17 pb 1113 Mg Sn Substance Substance Oxidized = Reducing Agent Reduced= Oxidizing Agent Cutz Zn +2 Pb Cu Cutz Ma +2 +2 Cutz Sn +2 2n 42 2n² Mg +2 2n pb Sn +2 Pb mg +2 Sn² Pb 'n +2 Sn mg Postlab #1: E cathode Postlab #1: E anode Postlab #1: Eº cell
Electrode 1 Cu Cu Cu Cu Zn Zn Zn Pb Pb Mg Electrode 2 Zn Pb Mg Sn Pb Mg Sn Mg Sn Sn Cell potential Ecell in V 0 O 0.9% Zn Сн 0401 v Pb Cu Cu 1o 480 mg •363 Sn 515 20 G Anode 692 482 2n Mg Bo 10121 Cathode + Ecell = Ecathode - E anode Cu рь 2n Sn рь 16-17 pb 1113 Mg Sn Substance Substance Oxidized = Reducing Agent Reduced= Oxidizing Agent Cutz Zn +2 Pb Cu Cutz Ma +2 +2 Cutz Sn +2 2n 42 2n² Mg +2 2n pb Sn +2 Pb mg +2 Sn² Pb 'n +2 Sn mg Postlab #1: E cathode Postlab #1: E anode Postlab #1: Eº cell
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I am trying to figure out how to fill in the last part of that chart that is supposed to come from What I did in the measured cell potential
![. (12) In Part I of the procedure, you measured the cell potential for a variety of combinations of
half cells. Use a standard reduction potential table in your textbook to calculate the expected
Eᵒcell using the formula Eºcell = Eºcathode - - E°anode. Calculate Eºcell for each combination
of cells. Show work for one calculation here, but you can enter the values in the table on page
6.
M = 0.581
S 8.99
1000
5.81
100
58.99
Actual concentration of conce
١٨ ٥٠٠ من one لسور
Ma
m-0098
0.098 but the](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3c9b7cf8-bc31-43fb-8f2d-f6ce11207b4a%2F2fb130c5-9261-44fc-b6a1-c2ba3c70bf05%2Fqbndo8c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:. (12) In Part I of the procedure, you measured the cell potential for a variety of combinations of
half cells. Use a standard reduction potential table in your textbook to calculate the expected
Eᵒcell using the formula Eºcell = Eºcathode - - E°anode. Calculate Eºcell for each combination
of cells. Show work for one calculation here, but you can enter the values in the table on page
6.
M = 0.581
S 8.99
1000
5.81
100
58.99
Actual concentration of conce
١٨ ٥٠٠ من one لسور
Ma
m-0098
0.098 but the
![Electrode 1
Cu
Cu
Cu
Cu
Zn
Zn
Zn
Pb
Pb
Mg
Electrode 2
Zn
Pb
Mg
Sn
Pb
Mg
Sn
Mg
Sn
Sn
Cell
potential
Ecell in V
0.976 Zn
Cai
оных трь си
10 480X
си
0
Anode
mg
•363 S Cu
515 2n
рь
2n
.692
482 2n
Ma
Bo
10/21
Cathode
Ecell = Ecathode - E anode
Sp
рь
16-17
pb
10113 Ma Sh
Substance
Oxidized =
Reducing
Agent
Zn
+2
Cu+2
Cut Pb
Cutz Ma
Cutz Sn
+2
Pb
42
2n+2
+2
Sn
+2
Pb ¹²
Substance
Reduced=
Oxidizing
Agent
mg
2n
Mg
2n
mg
+2
Sn2 Pb
+2
Sn
Postlab #1:
Eᵒcathode
Postlab #1:
E anode
Postlab #1:
Eºcell](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3c9b7cf8-bc31-43fb-8f2d-f6ce11207b4a%2F2fb130c5-9261-44fc-b6a1-c2ba3c70bf05%2F20w7lok_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Electrode 1
Cu
Cu
Cu
Cu
Zn
Zn
Zn
Pb
Pb
Mg
Electrode 2
Zn
Pb
Mg
Sn
Pb
Mg
Sn
Mg
Sn
Sn
Cell
potential
Ecell in V
0.976 Zn
Cai
оных трь си
10 480X
си
0
Anode
mg
•363 S Cu
515 2n
рь
2n
.692
482 2n
Ma
Bo
10/21
Cathode
Ecell = Ecathode - E anode
Sp
рь
16-17
pb
10113 Ma Sh
Substance
Oxidized =
Reducing
Agent
Zn
+2
Cu+2
Cut Pb
Cutz Ma
Cutz Sn
+2
Pb
42
2n+2
+2
Sn
+2
Pb ¹²
Substance
Reduced=
Oxidizing
Agent
mg
2n
Mg
2n
mg
+2
Sn2 Pb
+2
Sn
Postlab #1:
Eᵒcathode
Postlab #1:
E anode
Postlab #1:
Eºcell
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