Electricity: Kirchhoff's Rules An application of Kirchhoff's Rules to the circuit shown results in the following system of equations: 4 = I3 + I½ 24 – 611 – 313 = 0 | 12 + 24 – 611 – 61, = 0 %3D Find the currents I4 , I2, and I3. 12 V 24 V 50 20 Source: Ibid., Prob. 38, p. 791.

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Electricity: Kirchhoff's Rules An application of Kirchhoff's
Rules to the circuit shown results in the following system of
equations:
4 = I3 + I½
24 – 611 – 313 = 0
| 12 + 24 – 611 – 61, = 0
%3D
Find the currents I4 , I2, and I3.
12 V
24 V
50
20
Source: Ibid., Prob. 38, p. 791.
Transcribed Image Text:Electricity: Kirchhoff's Rules An application of Kirchhoff's Rules to the circuit shown results in the following system of equations: 4 = I3 + I½ 24 – 611 – 313 = 0 | 12 + 24 – 611 – 61, = 0 %3D Find the currents I4 , I2, and I3. 12 V 24 V 50 20 Source: Ibid., Prob. 38, p. 791.
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