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A 23-kVA, 2300/230-V, 60-Hz, step down transformer has the following resistance and leakage- reactance values: R=40, R2=0.040, X-120, and X=0.120. The transformer is operating at 75% of its rated load. If the power factor of the load is 0.866 leading. Determine the efficiency of the transformer. 9:50 1 a =10 Step2 b) Now Loud operetig ts°lo of its let, x = t5% E. Actuel load ou Pout - XxSx CESD trans formn Pout Pout rated load = 0:75 :. 0*子5×23×o866 14.94 KW ニ New Referring tla Loud ļ Secondary reaistances Pecinay Side 10 x o-04 - 4 r %3D 2 ox O•12 = - a la 10X 230 = 2300V ニ Step3 c) Now the ciocuit become8, RI

A 23-kVA, 2300/230-V, 60-Hz, step down transformer has the following resistance and leakage- reactance values: R=40, R2=0.040, X-120, and X=0.120. The transformer is operating at 75% of its rated load. If the power factor of the load is 0.866 leading. Determine the efficiency of the transformer. 9:50 1 a =10 Step2 b) Now Loud operetig ts°lo of its let, x = t5% E. Actuel load ou Pout - XxSx CESD trans formn Pout Pout rated load = 0:75 :. 0*子5×23×o866 14.94 KW ニ New Referring tla Loud ļ Secondary reaistances Pecinay Side 10 x o-04 - 4 r %3D 2 ox O•12 = - a la 10X 230 = 2300V ニ Step3 c) Now the ciocuit become8, RI

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Why Pout will not increase bu 75% So why we did not use (1+0.75)(S)Pf and only we use 0.75(s)(pf) why we did not increase it ?
A 23-kVA, 2300/230-V, 60-Hz, step down transformer has the following resistance and leakage- reactance values: R=40, R2=0.040, X-120, and X=0.120. The transformer is operating at 75% of its rated load. If the power factor of the load is 0.866 leading. Determine the efficiency of the transformer.
Transcribed Image Text:A 23-kVA, 2300/230-V, 60-Hz, step down transformer has the following resistance and leakage- reactance values: R=40, R2=0.040, X-120, and X=0.120. The transformer is operating at 75% of its rated load. If the power factor of the load is 0.866 leading. Determine the efficiency of the transformer.
9:50 1 a =10 Step2 b) Now Loud operetig ts°lo of its let, x = t5% E. Actuel load ou Pout - XxSx CESD trans formn Pout Pout rated load = 0:75 :. 0*子5×23×o866 14.94 KW ニ New Referring tla Loud ļ Secondary reaistances Pecinay Side 10 x o-04 - 4 r %3D 2 ox O•12 = - a la 10X 230 = 2300V ニ Step3 c) Now the ciocuit become8, RI
Transcribed Image Text:9:50 1 a =10 Step2 b) Now Loud operetig ts°lo of its let, x = t5% E. Actuel load ou Pout - XxSx CESD trans formn Pout Pout rated load = 0:75 :. 0*子5×23×o866 14.94 KW ニ New Referring tla Loud ļ Secondary reaistances Pecinay Side 10 x o-04 - 4 r %3D 2 ox O•12 = - a la 10X 230 = 2300V ニ Step3 c) Now the ciocuit become8, RI
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