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Step 1 (Quesfion Step 2 Step 3 Fisst coente and lebels. Node a) a Ciacuit diagpam with the elemeuts Vs = Va 6) CCXLSR+Rt LS LS v6) solurion!- Vs = Va@) LRS+R+Ls Amlying kelt Node @ Souote WHoge inteming amut zsutgaingameut VsXL = Va(4) - vas) + va($)-0 VeX L Vals) = pagallel Conmeetion f capacitor and indluctod Yes Vs - sva (s) Above Ele toical ciocuit Converted into S-domain x + vae) RLC we Know that Vs - sva(s) L.T Va@2 = RS s+ tet ac LS LOT LC L Vs Yes RS RS Va(s) = Vs RS LT Laplece toans fom vs/RC s4 5/Re +%c Vs est+ V (s)= Va) = %3D +> Load vOltage RS Step 4 Step 5 Step 6 VL 6) = Vs 1R C LS Vt)- vsē Sin Vs/RC 29b=5/Rc Re te 246=1/RC 26=R Vs X 2RC vs/RC R C Vs Ic II ($)= ZRC RLCS (s4$/RC+) time VSIRC Because domain Output or toad side voitage L (S)= 2 we Kn Cerbseu I.LT y Sinat TRicing invease laplece bensfom す Vs RC e Sin Vs xe RC

Step 1 (Quesfion Step 2 Step 3 Fisst coente and lebels. Node a) a Ciacuit diagpam with the elemeuts Vs = Va 6) CCXLSR+Rt LS LS v6) solurion!- Vs = Va@) LRS+R+Ls Amlying kelt Node @ Souote WHoge inteming amut zsutgaingameut VsXL = Va(4) - vas) + va($)-0 VeX L Vals) = pagallel Conmeetion f capacitor and indluctod Yes Vs - sva (s) Above Ele toical ciocuit Converted into S-domain x + vae) RLC we Know that Vs - sva(s) L.T Va@2 = RS s+ tet ac LS LOT LC L Vs Yes RS RS Va(s) = Vs RS LT Laplece toans fom vs/RC s4 5/Re +%c Vs est+ V (s)= Va) = %3D +> Load vOltage RS Step 4 Step 5 Step 6 VL 6) = Vs 1R C LS Vt)- vsē Sin Vs/RC 29b=5/Rc Re te 246=1/RC 26=R Vs X 2RC vs/RC R C Vs Ic II ($)= ZRC RLCS (s4$/RC+) time VSIRC Because domain Output or toad side voitage L (S)= 2 we Kn Cerbseu I.LT y Sinat TRicing invease laplece bensfom す Vs RC e Sin Vs xe RC

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Can someone help me explain the DIAGRAM / EVERY STEP, how and why with regards to the solution and also the laplace transformation.

Step 1 (Quesfion Step 2 Step 3 Fisst coente and lebels. Node a) a Ciacuit diagpam with the elemeuts Vs = Va 6) CCXLSR+Rt LS LS v6) solurion!- Vs = Va@) LRS+R+Ls Amlying kelt Node @ Souote WHoge inteming amut zsutgaingameut VsXL = Va(4) - vas) + va($)-0 VeX L Vals) = pagallel Conmeetion f capacitor and indluctod Yes Vs - sva (s) Above Ele toical ciocuit Converted into S-domain x + vae) RLC we Know that Vs - sva(s) L.T Va@2 = RS s+ tet ac LS LOT LC L Vs Yes RS RS Va(s) = Vs RS LT Laplece toans fom vs/RC s4 5/Re +%c Vs est+ V (s)= Va) = %3D +> Load vOltage RS
Transcribed Image Text:Step 1 (Quesfion Step 2 Step 3 Fisst coente and lebels. Node a) a Ciacuit diagpam with the elemeuts Vs = Va 6) CCXLSR+Rt LS LS v6) solurion!- Vs = Va@) LRS+R+Ls Amlying kelt Node @ Souote WHoge inteming amut zsutgaingameut VsXL = Va(4) - vas) + va($)-0 VeX L Vals) = pagallel Conmeetion f capacitor and indluctod Yes Vs - sva (s) Above Ele toical ciocuit Converted into S-domain x + vae) RLC we Know that Vs - sva(s) L.T Va@2 = RS s+ tet ac LS LOT LC L Vs Yes RS RS Va(s) = Vs RS LT Laplece toans fom vs/RC s4 5/Re +%c Vs est+ V (s)= Va) = %3D +> Load vOltage RS
Step 4 Step 5 Step 6 VL 6) = Vs 1R C LS Vt)- vsē Sin Vs/RC 29b=5/Rc Re te 246=1/RC 26=R Vs X 2RC vs/RC R C Vs Ic II ($)= ZRC RLCS (s4$/RC+) time VSIRC Because domain Output or toad side voitage L (S)= 2 we Kn Cerbseu I.LT y Sinat TRicing invease laplece bensfom す Vs RC e Sin Vs xe RC
Transcribed Image Text:Step 4 Step 5 Step 6 VL 6) = Vs 1R C LS Vt)- vsē Sin Vs/RC 29b=5/Rc Re te 246=1/RC 26=R Vs X 2RC vs/RC R C Vs Ic II ($)= ZRC RLCS (s4$/RC+) time VSIRC Because domain Output or toad side voitage L (S)= 2 we Kn Cerbseu I.LT y Sinat TRicing invease laplece bensfom す Vs RC e Sin Vs xe RC
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