Ekkt bi Each parent has the which consists of the Part genotype brown/ bive, of alleles that determine eye color, and each Parent Contributes to one of those in the Child. ASSUme the child has one brown allele, that Color will dominate the Childs eyes being brawn. -List Possible outcomes. - Whats the probability a child of these that parents will have blue/bive genotype is? -Probability it will have brown 2 eyes.

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Ekatl
Each Parent has the
genotype brown/ bive,
which consists of the Pail
of alleles that determine
eye color, and each
Parent
Contributes the one
of those in the Child.
ASSUme the child has.
one brown allele, that
Color will dominate the
Childs eyes being brown.
-List Possible outcomes.
Whats the probability
that
a child of these
parents will have
blue/bive genotype is?
Probability it will have
brown 2
eyes
Transcribed Image Text:Ekatl Each Parent has the genotype brown/ bive, which consists of the Pail of alleles that determine eye color, and each Parent Contributes the one of those in the Child. ASSUme the child has. one brown allele, that Color will dominate the Childs eyes being brown. -List Possible outcomes. Whats the probability that a child of these parents will have blue/bive genotype is? Probability it will have brown 2 eyes
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Step 1

Given that

Each parent has the genotype brown/blue, Which Consists of the pair of alleles that determine. eye color, and each Parent of those in the Child. Contributes the one Assume the child has one brown allele, that Color will dominate the Childs eyes being brown.

We have to find 

a..List Possible outcomes: 

b..Whats the Probability that a Child of these Parents will have blue/blue genotype 

c..Probability it will have brown  eyes

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