Eight percent of the population is infected with Herpes simplex-2 virus (HSV2). If you select four individuals at random from a population, a. What is the probability of finding exactly 3 individuals with HSV2? b. What is the probability of finding at least one HSV2-positive individual in the sample? [HINT: All possibilities include 1 person has HSV2, 2 people have HSV2, 3 people have HSV2, or 4 people have HSV2; so if you added all those together you would have a probability of 1. First find Pr(X=0), and Pr(X ≥ 1)=1- Pr(X=0).]

Eight percent of the population is infected with Herpes simplex-2 virus (HSV2). If you select four individuals at random from a population, a. What is the probability of finding exactly 3 individuals with HSV2? b. What is the probability of finding at least one HSV2-positive individual in the sample? [HINT: All possibilities include 1 person has HSV2, 2 people have HSV2, 3 people have HSV2, or 4 people have HSV2; so if you added all those together you would have a probability of 1. First find Pr(X=0), and Pr(X ≥ 1)=1- Pr(X=0).]

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

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Eight percent of the population is infected with Herpes simplex-2 virus (HSV2). If you select four
individuals at random from a population,
a. What is the probability of finding exactly 3 individuals with HSV2?
b. What is the probability of finding at least one HSV2-positive individual in the sample?
[HINT: All possibilities include 1 person has HSV2, 2 people have HSV2, 3 people have HSV2, or
4 people have HSV2; so if you added all those together you would have a probability of 1. First
find Pr(X=0), and Pr(X ≥ 1)=1- Pr(X=0).]

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